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oee [108]
2 years ago
11

The Pit BBQ food truck sells two combo packs of ribs and brisket. Combo A contains 10 oz of brisket and 16 oz of ribs and sells

for $21.25. Combo B contains 20 oz of brisket and 8 oz of ribs and sells for $30.00. They plan to use no more than 400 oz of brisket and 384 oz of ribs and they want to sell at most 28 combo packs. How many of each combo should be made to maximize revenue ?
Mathematics
1 answer:
GenaCL600 [577]2 years ago
3 0

The maximum revenue is $700 which is at 16 combo A and 12 combo B.

<h3>Inequality</h3>

An inequality is an expression that shows the non equal comparison of two or more numbers and variables.

Let x represent the number of combo A and y represent the number of combo B, hence:

10x + 20y ≤ 400 (1)

Also:

x + y ≤ 28   (2)

The solution is at (16,12). Hence:

Revenue = 21.25 * 16 + 30 * 12 = $700

The maximum revenue is $700 which is at 16 combo A and 12 combo B.

Find out more on Inequality at: brainly.com/question/24372553

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