Given a friction force of 1.10 N, how fast is a 0.510 kg book moving in 0.50 s if it starts at rest and you are applying a force
1 answer:
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Answer:
894 electrons
Explanation:
The electrostatic force between the two charges is given by:
where we have
is the force
k is the Coulomb's constant
q1 = q2 =q is the magnitude of the charge on each sphere
r = 20.0 cm = 0.20 m is the distance between the two spheres
Substituting and solving for q, we find the charge on each sphere:
And since each electron has a charge of
the net charge on each sphere will be given by
where N is the number of excess electrons; solving for N,