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ivanzaharov [21]
3 years ago
8

What body parts were scientists wanting to image that prompted the development of the CT scanner

Physics
1 answer:
zalisa [80]3 years ago
4 0

Answer:

The head

Explanation:

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A 190 N child is in a swing that is attached to ropes 2.10 m long. Find the gravitational potential energy of the child-Earth sy
Alekssandra [29.7K]

Answer:

a) Gravitational potential energy = 399 J

b) Gravitational potential energy = 66.5 J

c) Gravitational potential energy = 0 J

Explanation:

Hi there!

Please, see the attached figure for a better understanding of the problem.

a) When the ropes are horizontal, the height of the child, relative to the child's lowest position, is 2.10 m (see figure).

The gravitational potential energy is calculated as follows:

PE = mgh

Where:

PE = potential energy.

mg = weight of the child

h = height.

Then when the ropes are horizontal, the potential energy will be:

PE = 190 N · 2.10 m = 399 J

b) When the ropes make a 34.0° with the vertical, the height of the child is 2.10 m minus x (see figure). To find x, we can use trigonometry of right triangles:

cos angle = adjacent side / hypotenuse

cos 34.0° = x / 2.10 m

x = 2.10 m · cos 34.0° = 1.75 m

Then, the height of the child relative to the lowest position is

(2.10 m - 1.75 m) = 0.35 m

Therefore, the gravitational potential energy will be:

PE = 190 N · 0.35 m

PE = 66.5 J

c) When the child is at the bottom of the circular arc the height is zero (the child is at the lowest position), then, the gravitational potential energy will be zero.

6 0
3 years ago
Two pieces of cotton have ____ charges and they ___ each other
Aliun [14]
Like . . . repel
unlike . . . attract
positive . . . repel
negative . . . repel
7 0
3 years ago
A 47 kg mass is moving across a horizontal surface at 8 m/s. What is the force required to bring the mass to a stop in 4.1 secon
crimeas [40]

Answer:

Force = -91.7 Newton

Explanation:

Given the following data;

Mass = 47 kg

Time = 4.1 seconds

Initial velocity = 8 m/s

Since the object comes to a stop, its final velocity would be equal to zero.

To find the force required to bring it to stop;

First of all, we would determine the acceleration of the object;

Mathematically, acceleration is given by the equation;

Acceleration (a) = \frac{final \; velocity  -  initial \; velocity}{time}

Substituting into the equation;

a = \frac{0 - 8}{4.1}

a = \frac{-8}{4.1}

Acceleration, a = -1.95 m/s²

Next, we would determine the force required to bring the object to stop;

Force = mass * acceleration

Force = 47 * -1.95

Force = -91.65 ≈ 91.7 Newton

6 0
3 years ago
Help me please on this
Norma-Jean [14]
So what u do is 2112393921010
6 0
2 years ago
A wire 43.7 cm long carries a 0.450 A current in the positive direction of an x axis through a magnetic field with an x componen
zubka84 [21]

Answer: Force on a current-carrying wire

F = I L x B

where F, L and B are all vectors, x means cross product.

I = 0.410 A

L = (0.689, 0, 0) m

B = (0, 0.000330, 0.0110) T

F = 0.410*(0.689, 0, 0) x (0, 0.000330, 0.0110) N

= (0, -0.410*0.689*0.0110, 0.410*0.689*0.000330)

= (0, -3.11*10^-3, 9.32*10^-5) N

so

a) Fx = 0

b) Fy = -3.11*10^-3 N

c) Fz = 9.32*10^-5 N

32

Explanation: make me brainlyest please i really need it please

3 0
3 years ago
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