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kirill [66]
3 years ago
7

An example of acceleration

Physics
1 answer:
TEA [102]3 years ago
5 0

Answer:

Explanation:

Newton’s Second Law of Motion says that acceleration (gaining speed) happens when a force acts on a mass (object). Riding your bicycle is a good example of this law of motion at work. Your bicycle is the mass.

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What phase are daughter cells in as a result of mitosis
NemiM [27]
They are in interphase
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Upon examining layer M, you find that it contains a small proportion of the radioactive isotope - Potassium-40, which decays int
Westkost [7]

Answer:

t = 2.6 billion years

Explanation:

If potassium becomes 25% of its initial value

so we can say it becomes half two times

as we know that 25% means it is 1/4 times of initial value

so we will have

N = N_o e^{-\lambda t}

here we know that

N = 0.25 N_o

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ln 4 = (\frac{ln 2}{T_{1/2}}) t

t = 2 T_{1/2}

t = 2(1.3 billion \: years)

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4 0
3 years ago
A sound wave traveling downward with a speed of about 4,000 m/s suddenly slows to 1,500 m/s not far below the earth’s surface. w
Ksivusya [100]

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3 0
4 years ago
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The potential energy of a catapult was completely converted into kinetic energy by releasing a small stone with a mass of 20 gra
DerKrebs [107]

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20 grams = 0.02 kilogram

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4 0
3 years ago
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Anna is sitting in a moving cart and throws a ball straight up. Theoretically, the ball should land in the cart, but it lands on
Likurg_2 [28]

Answer:

Reason for the difference in the ranges of the ball and the cart:

"the average speed of the cart is less than the instant speed of the cart at the time of throwing the ball".

Explanation:

Assuming that the air friction is negligible.

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So, the range of the ball is more than the range of the cart in the same time interval.

Let the instant speed of the cart is v m/s  at the time of throwing the ball in the vertically upward direction, so the speed of the ball in the horizontal direction = v m/s.

Let t be the total time of flight of the ball.

As the gravitational force is acting in the downward direction so it will not change the horizontal velocity of the ball.

So, the range covered by the ball = vt m.

Let u be the average speed of the cart for the time t s (same as the time of flight of ball).

So, the distance by the cart = ut m

As the range of the ball is more than the range of the cart in the same time interval, so

vt > ut \\\\\Rightarrow v>u.

So, the reason for the difference in the ranges of the ball and the cart is "the average speed of the cart is less than the instant speed of the cart at the time of throwing the ball".

5 0
3 years ago
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