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stepladder [879]
3 years ago
9

The width of a particular microwave oven is exactly right to support a standing-wave mode. Measurements of the temperature acros

s the oven show that there are cold spots at each edge of the oven and at three spots in between. The wavelength of the microwaves is 12 cm. a. How wide is the oven?
b. What is the frequency of the microwaves?
Physics
1 answer:
Tems11 [23]3 years ago
7 0

Answer:

a) l = 24 cm

b) υ = 2.5 × 10⁹ Hz

Explanation:

given,                      

wavelength of microwave = 12 cm

length of microwave        

           = 2 × λ                    

           = 2 × 12                    

        l = 24 cm

microwave is an electromagnetic wave speed is 3 × 10⁸ m/s

v = υ λ                

υ = \dfrac{v}{\lambda}            

υ = \dfrac{3 \times 10^8}{0.12}

υ = 2.5 × 10⁹ Hz

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A disk has 128 tracks of 32 sectors each, on each surface of eight platters. The disk spins at 3600 RPM and takes 15 ms to move
Serga [27]

Answer:

the longest time needed to read an arbitrary sector located anywhere on the disk is 2971.24 ms

Explanation:

 Given the data in the question;

first we determine the rotational latency

Rotational latency = 60/(3600×2) = 0.008333 s = 8.33 ms

To get the longest time, lets assume the sector will be found at the last track.

hence we will access all the track, meaning that 127 transitions will be done;

so the track changing time = 127 × 15 = 1905 ms

also, we will look for the sectors, for every track rotations that will be done;

128 × 8.33 = 1066.24 ms

∴The Total Time = 1066.24 ms + 1905 ms

Total Time = 2971.24 ms

Therefore, the longest time needed to read an arbitrary sector located anywhere on the disk is 2971.24 ms

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3 years ago
A car headed north at 15.0 m/s experiences an acceleration of 2.50 m/s2 for 3.00 s. What is the final velocity of the car?
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4 0
2 years ago
Name and describe at least SIX engineering challenges that the Mars copter, Ingenuity, had to overcome in order to be built/to t
Y_Kistochka [10]

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Explanation:

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4 0
3 years ago
A golf ball has a mass of 120g. Calculate its increase in mass when it is travelling at 40ms1. What is this as a percentage of i
kicyunya [14]

Answer:

Percentage=8.889\times 10^{-13}%

Explanation:

From special theory of relativity the dynamic mass m is related with the rest mass m_{0}of the body as

m=\frac{m_{0} }{\sqrt{1-\frac{v^{2} }{c^{2} } } }

Here, c is the speed of light and v is the velocity of object.

Given mass of the golf ball is 120 g.

m=\frac{120 }{\sqrt{1-\frac{(40)^{2} }{(3\times 10^{8} )^{2} } } }\\m=120(1-\frac{(40)^{2} }{(3\times 10^{8}) ^{2} })^{-\frac{1}{2} } \\

Now applying the binomial theorem and solve the above equation.

m=(1+\frac{1}{2}(\frac{40}{3\times 10^{8} }) ^{2} )\\m=120(1+8.889\times 10^{-15})

Therefore, increase in mass is,

\Delta m=120\times 8.889\times 10^{-15} \\\Delta m=10.6668\times 10^{-13} g

Now percentage of increase in mass with rest mass is,

Percentage=\frac{10.6668\times 10^{-13} g}{120g} \times 100\\Percentage=8.889\times 10^{-13}

Therefore, the percentage of increase in mass with rest mass is Percentage=8.889\times 10^{-13}.

4 0
4 years ago
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