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Sveta_85 [38]
4 years ago
9

A car goes from 5 m/s to 25 m/s in 6 s. What is the acceleration of the car?

Physics
1 answer:
damaskus [11]4 years ago
3 0

Answer:

5m/s

Explanation:

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If 270 wats of power is used in 42 seconds how much work is done ?
pentagon [3]

Answer:

power is given by work done divide time taken

P=w/t

therefore Pt=w

270x42=11,340.J

6 0
3 years ago
A basketball player shoots toward a basket 4.9 m away and 3.0 m above the floor. If the ball is released 1.8 m above the floor a
Zolol [24]

Answer:

  v₀ = 6.64 m / s

Explanation:

This is a projectile throwing exercise

          x = v₀ₓ t

          y = y₀ + v_{oy} t - ½ g t²

In this case they indicate that y₀ = 1.8 m and the point of the basket is x=4.9m y = 3.0 m

         

the time to reach the basket is

        t = x / v₀ₓ

we substitute

        y- y₀ = \frac{ v_o \ x \ sin \theta  }{ v_o \ cos \theta} - \frac{1}{2} g \ \frac{x^2 }{v_o^2 \ cos^2 \theta }

        y - y₀ = x tan θ - \frac{ g \ x^2 }{ 2 \ cos^2 \theta } \ \frac{1}{v_o^2 }

         

we substitute the values

        3 -1.8 = 3.0 tan 60 - \frac{ 9.8 \ 3^2 }{2 \ cos^2 60 } \ \frac{1}{v_o^2}

        1.2 = 5.196 - 176.4 1 / v₀²

        176.4 1 / v₀² = 3.996

        v₀ = \sqrt{ \frac{ 176.4}{3.996} }

        v₀ = 6.64 m / s

6 0
3 years ago
Which of the following is an example of an allocation decision?|
Oksana_A [137]

Answer:

The answer is D- Coal is set aside to burn as heating fuel

Explanation:

Allocation decisions set aside resources for a specific purpose.

7 0
4 years ago
Read 2 more answers
A research vessel is mapping the bottom of the ocean using sonar. It emits a short sound pulse called "ping" downward. The frequ
Svetradugi [14.3K]

Answer:

d = 4180.3m

wavelengt of sound is 0.251m

Explanation:

Given that

frequency of the sound is 5920 Hz

v=1485m/s

t=5.63s

let d represent distance from the vessel to the ocean bottom.

an echo travels a distance equivalent to 2d, that is to and fro after it reflects from the obstacle.

velocity=\frac{distance}{time}\\\\ v=\frac{2d}{t} \\\\vt=2d\\\\d=\frac{vt}{2}

d=\frac{1485*5.63}{2}\\d= 4180.3m

wavelengt of sound is \lambda = v/f

= (1485)/(5920)

= 0.251 m

7 0
3 years ago
Calculate the entropy change that occurs when 1.0kg of water at 20.00 C is mixed with 2.0kg of water at 80.00 C
SOVA2 [1]

Answer:

The change in entropy ΔS = 0.0011 kJ/(kg·K)

Explanation:

The given information are;

The mass of water at 20.0°C = 1.0 kg

The mass of water at 80.0°C = 2.0 kg

The heat content per kg of each of the mass of water is given as follows;

The heat content of the mass of water at 20.0°C = h₁ = 83.92 KJ/kg

The heat content of the mass of water at 80.0°C = h₂ = 334.949 KJ/kg

Therefore, the total heat of the the two bodies = 83.92 + 2*334.949 = 753.818 kJ/kg

The heat energy of the mixture =

1 × 4200 × (T - 20) = 2 × 4200 × (80 - T)

∴ T = 60°C

The heat content, of the water at 60° = 251.154 kJ/kg

Therefore, the heat content of water in the 3 kg of the mixture = 3 × 251.154 = 753.462

The change in entropy ΔS = ΔH/T = (753.818 - 753.462)/(60 + 273.15) = 0.0011 kJ/(kg·K).

8 0
3 years ago
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