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levacccp [35]
3 years ago
5

Q7 Q26.) Find the quotient of the complex numbers and leave your answer in polar form.

Mathematics
1 answer:
ANTONII [103]3 years ago
6 0
For any complex numbers in polar form c_1 = r_1\text{cis}(\theta_1),\ c_2 = r_2\text{cis}(\theta_2)

(Where \text{cis}(\theta) = \cos(\theta) + i\sin(\theta))

Then \dfrac{c_1}{c_2} = \dfrac{r_1}{r_2}\text{cis}(\theta_1-\theta_2)

So then for your problem, that would be

\dfrac{z_1}{z_2} = \dfrac37\text{cis}\left(\dfrac\pi8-\dfrac\pi9\right)=\boxed{\dfrac37\text{cis}\left(\dfrac\pi{72}\right)}

So that would be \boxed{\dfrac37\left(\cos\left(\dfrac\pi{72}\right)+i\sin\left(\dfrac\pi{72}\right)\right)}

Hope this helps.
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Which of the following expressions is equivalent to 3p^4
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<span>Assuming that this is referring to the same list of options that was posted before with this question, the correct response was the first one, although I forget what it was. </span>
3 0
3 years ago
Is the given point interior , exterior, or on the circle k (x+2)2 + (y-3)2 =18 P (8,4)
Mnenie [13.5K]
One way would be to find the distance from the point to the center of the circle and compare it to the radius

for
(x-h)^2+(y-k)^2=r^2
the center is (h,k) and the radius is r

and the distance formula is
distance between (x_1,y_1) and (x_2,y_2) is
D=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}


r=radius
D=distance form (8,4) to center

if r>D, then (8,4) is inside the circle
if r=D, then (8,4) is on the circle
if r<D, then (8,4) is outside the circle


so
(x+2)^2+(y-3)^2=18
(x-(-2))^2+(y-3)^2=(\sqrt{18})^2
(x-(-2))^2+(y-3)^2=(3\sqrt{2})^2

the radius is 3\sqrt{2}
center is (-2,3)

find distance between (8,4) and (-2,3)

D=\sqrt{(8-(-2))^2+(4-3)^2}
D=\sqrt{(8+2)^2+(1)^2}
D=\sqrt{10^2+1}
D=\sqrt{100+1}
D=\sqrt{101}




r=3\sqrt{2}≈4.2
D=\sqrt{101}≈10.04

do r<D

(8,4) is outside the circle

6 0
3 years ago
How do I create an equation and solve for x
vekshin1

Answer:

Equation: (2x + 30) + 106 = 180

x = 22°

Step-by-step explanation:

<u>We know that the missing angle from within the triangle and the expression 2x + 30 makes 180 so we can say;</u>

180 - (33 + 41) = missing angle

180 - 74 = missing angle

<u>106</u>°<u> = missing angle</u>

Now we can set up our equation to solve for x:

(2x + 30) + missing angle = 180°

<u>(2x + 30) + 106 = 180</u>°<u> => This would be our equation:</u>

Now let's solve:

2x + 30 + 106 = 180°

2x + 136 = 180

2x = 180 - 136

2x = 44

x = 44/2

<u>x = 22°</u>

Hope this helps!

6 0
3 years ago
Read 2 more answers
The diameter of a circle has endpoints P(-6,-11 ) and Q(4, 7). Write an equation for the circle. Be sure to show and explain all
MrMuchimi

Answer:

(x + 1)^2 + (y + 2)^2 = 106

Step-by-step explanation:

The formula for a circle is

(x - h)^2 + (y - k)^2 = r^2

Where (h, k) is the center of the circle and r is the raadius

--------------------------------------

The center is the midpoint of the diameter end points

(h, k) = ( (-6 + 4)/2 , (-11 + 7)/2 )

(h, k) = (-1, -2)

The radius is the distance from the center to an endpoint

Using (h, k) and Q

r^2 = (4 - -1)^2 + (7 - -2)^2

r^2 = 5^2 + 9^2

r^2 = 106

-------------------------------

Plug into the circle formula

(x + 1)^2 + (y + 2)^2 = 106

7 0
3 years ago
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