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deff fn [24]
3 years ago
7

Box A has a volume of 512 cubic meters. Box B is similar to box A. To create Box B, Box A's dimensions were divided by 2. What i

s the volume of Box B?
Mathematics
1 answer:
bearhunter [10]3 years ago
5 0

Answer : The volume of box B is 64m^3

Step-by-step explanation :

Given :

Volume of box A = 512 cubic meter

Let us assumed that the box A and box B are cubes and the dimensions of cube are same i.e, 'a'.

Volume of box A = V = a\times a\times a=a^3

As per question,

When dimensions of box A divided by 2 then the volume of box B will be:

Volume of box A = V' = \frac{a}{2}\times \frac{a}{2}\times \frac{a}{2}=\frac{a^3}{8}

As the box B is similar to box A. So, the volume of box B will be:

Volume of box B = V' = \frac{a^3}{8}

V'=\frac{a^3}{8}=\frac{V}{8}

V'=\frac{512m^3}{8}=64m^3

Therefore, the volume of box B is 64m^3

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A bank account has a beginning of 560.00. After 6 months, the balance in the account has increased to 572.60. What interest rate
MaRussiya [10]

This is tricky because we are given the interest rate for the year but the problem is figureing the interest for 6 months or 1/2 year. We will have to double the difference before solving for the yearly interest.

572.60 - 560.00 = 12.60 interest added for 6 months x 2 = 25.20 for 12 months

(This problem assumes the interest will stay the same the next 6 months)

We need to find what percent 25.20 is to our original balance.

25.20/560 = x / 100

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4 0
3 years ago
Which function has an average rate of change of -4 over the interval [-2,2]?
kolbaska11 [484]

Only p(x) has an average rate of change of -4 over [-2, 2].

Find the average rate of change of each given function over the interval [-2, 2]]:

The average rate of change of m(x) over [-2, 2]:

<h3>What is the average rate?</h3>

The average rate of change = \frac{m(b)-m(a)}{b-a}

Where, a = -2, m(a) = -12

b = 2, m(b) = 4

Plug the values into the equation

The average rate of change

=\frac{4-(-12)}{2-(-2)} =\frac{16}{4}

The average rate of change = 4

The average rate of change of n(x) over [-2, 2]:

The average rate of change = \frac{n(b)-n(a)}{b-a}

Where, a = -2, n(a) = -6

b = 2, n(b) = 6

Plug the values into the equation

The average rate of change

=\frac{6-(-6)}{2-(-2)} \\=\frac{12}{4}

The average rate of change = 3

The average rate of change of q(x) over [-2, 2]:

The average rate of change = \frac{q(b)-q(a)}{b-a}

Where, a = -2, q(a) = -4

b = 2, q(b) = -12

Plug the values into the

The average rate of change = \frac{-4-12}{2-(-2)}

= \frac{-16}{4}

The average rate of change = -2

The average rate of change of p(x) over [-2, 2]:

The average rate of change = \frac{p(b)-p(a)}{b-a}

Where, a = -2, p(a) = 12

b = 2, p(b) = -4

Plug the values into the equation

The average rate of change = \frac{-4-12}{2-(-2)}

=\frac{-16}{4}

The average rate of change = -4

The answer is D.

Only p(x) has an average rate of change of -4 over [-2, 2].

To learn more about the average rate of visit:

brainly.com/question/8728504

#SPJ1

8 0
1 year ago
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