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dalvyx [7]
2 years ago
8

Q6.4. You are studying a population of wild coyotes and notice that every three years there is an epidemic of a bacterial

Biology
1 answer:
Setler79 [48]2 years ago
5 0
I think it’s a or c but I’m not good at these types of things
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katovenus [111]

Answer:

light mice, because they blend in with their enviorment

Explanation:

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2 years ago
A cross is made between homozygous wild-type female Drosophila (a^+ a^+ b^+ b^+ c^+ c^+) and triple-mutant males (aa bb cc) (the
marusya05 [52]

Answer:

a is the middle gene.

Distance [b-a]= 24.7 mu

Distance [a-c]= 15.8 mu

Distance [b-a} = 40.5 mu

Explanation:

A homozygous wild-type female drosophila (a⁺b⁺c⁺/a⁺b⁺c⁺) is crossed with a homozygous recessive male (abc/abc). <u>The order of the genes here is arbitrary. </u>

The F1 is heterozygous for the three genes (a⁺b⁺c⁺/abc). The F1 females were test crossed (crossed with abc/abc males).

The F2 shows the following phenotypic ratios:

  • 320 a⁺b⁺c⁺
  • 308 a b c
  • 102 a⁺ b c⁺
  • 112 a b⁺ c
  • 66  a⁺ b⁺ c
  • 59 a b c⁺
  • 18 a⁺ b c
  • 15 a b⁺ c⁺

Total = 1000

The male parent is homozygous recessive for the 3 genes, so the observed phenotypes of the offspring correspond to the gametes received from the mother.

Recombination during meiosis is a rare event, so the most abundant gametes are always the parentals:  a⁺b⁺c⁺ and abc.

The least abundant gametes, following the same logic, are the double crossovers (DCO): a⁺bc and ab⁺c⁺.

<h3><u>1st. Determine the gene order</u></h3>

Compare the parental and the DCO gametes. The allele that is switched corresponds to the middle gene. In this case, gene a is in the middle of the other two.

<h3><u>2nd Determine the single crossover gametes</u></h3>

The F1 mother that generated all 8 types of gametes had the genotype b⁺a⁺c⁺/bac (correct order of genes).

  • The single crossover (SCO) gametes resulting from recombination between genes b and a are b⁺ac and ba⁺c⁺.
  • The single crossover (SCO) gametes resulting from recombination between genes a and c are b⁺a⁺c and bac⁺.
<h3><u>3) Calculate the recombination frequencies between genes </u></h3>

Recombination frequency (RF) = #Recombinants/Total progeny

  • RF [b-a]= (102+112+18+15)/1000= 0.247
  • RF [f-br]= (66+59+18+15)/1000= 0.158
<h3><u /></h3><h3><u>4) Calculate the distance in map units </u></h3>

Distance (mu) = RF x 100

Distance [b-a]= 0.247 × 100 = 24.7 mu

Distance [a-c]= 0.158 × 100 = 15.8 mu

Distance [b-a} = 24.7 mu + 15.8 mu = 40.5 mu

<h3><u>The gene map therefore looks like: </u></h3>

b------------24.7 mu--------------------------a---------15.8 mu-----------c

4 0
3 years ago
Why does the cell go through elaborate process to convert glucose into carbon dioxide and water?
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Cellular<span> Respiration. </span>Cellular<span> respiration is the </span>process<span> of oxidizing food molecules, like </span>glucose<span>, to </span>carbon dioxide and water<span>. The energy released is trapped in the form of ATP for use by all the energy-consuming activities of the </span>cell<span>.

</span>
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Briefly describe the relationship between the old testament and the new testament. quizlet
Colt1911 [192]
The New Testament does not replace the old testament, however it fulfills it. Without the New Testament the Old Testament would just be a collection of tragic stories and unfulfilled promises. The Old Testament is the gradual unfolding of Gods plan of salvation
3 0
3 years ago
Read 2 more answers
The diagram shows two charged objects, A and B.
ale4655 [162]

Answer:

A: positive

B: negative

Explanation:

Hope it helps.

3 0
2 years ago
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