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2 years ago

Find the value of x if the perimeter is 30. Х X +3 2x – 1

Mathematics

1 answer:

KatRina [158]2 years ago

4 0

Answer:

x = 7

Step-by-step explanation:

The perimeter of triangle is A = a + b + C, the sum of the three sides.

P = 30 and the three sides are x + (2x - 1) + (x + 3)

30 = x + (2x - 1) + (x + 3) combine like terms together

30 = (x + 2x + x) + (-1 + 3) Add like terms

30 = 4x + 2

30 - 2 = 4x Subtract 2

28 = 4x Simply

7 = x Divide by 4

Check x = 7; x + 3 ; 2x - 1 7 + 10 + 13 = 30

7 + 3 = 10 2(7) - 1

14 - 1 = 13

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Kyla makes a triangular school pennant. The area of the triangle is 180 square inches. The base of the pennant is z inches long.

kykrilka [37]

We can represent the base as z and the height as 2z+6. We are going to use the formula A=1/2*b*h and solve for z
180=1/2*z*(2z+6)
360=2z^2+6z
0=2z^2+6z-360
0=2(z^2+3z-180)
0=(z+15)(z-12)
So z=-15 and 12 but it must be positive so then the base is equal to 12

When we plug this into 2z+6 we get 30 for the height
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3 years ago

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3 years ago

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3 years ago

Read 2 more answers

Find 6% of $5.65 and round the product to the nearest cent.

Leviafan [203]

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3 years ago

Suppose that X has an exponential distribution with mean equal to 10. Determine the following: a. P(X > 10) b. P(X > 20) c

GrogVix [38]

Answer:

(a) The value of P (X > 10) is 0.3679.

(b) The value of P (X > 20) is 0.1353.

(d) The value of x is 30.

Step-by-step explanation:

The probability density function of an exponential distribution is:

$f(x)=\lambda e^{-\lambda x};\ x>0, \lambda>0$

The value of E (X) is 10.

The parameter λ is:

$\lambda=\frac{1}{E(X)}=\frac{1}{10}=0.10$

(a)

Compute the value of P (X > 10) as follows:

$P(X>10)=\int\limits^{\infty}_{10} {0.10 e^{-0.10 x}} \, dx \\=0.10\int\limits^{\infty}_{10} { e^{-0.10 x}} \, dx\\=0.10|\frac{e^{-0.10 x}}{-0.10} |^{\infty}_{10}\\=|e^{-0.10 x} |^{\infty}_{10}\\=e^{-0.10\times10}\\=0.3679$

Thus, the value of P (X > 10) is 0.3679.

(b)

Compute the value of P (X > 20) as follows:

$P(X>20)=\int\limits^{\infty}_{20} {0.10 e^{-0.10 x}} \, dx \\=0.10\int\limits^{\infty}_{20} { e^{-0.10 x}} \, dx\\=0.10|\frac{e^{-0.10 x}}{-0.10} |^{\infty}_{20}\\=|e^{-0.10 x} |^{\infty}_{20}\\=e^{-0.10\times20}\\=0.1353$