Which kind of image can never be projected and forms where light rays appear to originate? virtual real inverted enlarged.

Displacement is the difference between the initial position and the____ position of an object

SOVA2 [1]

<span>Displacement is the difference between the initial position and the FINAL position of an object.

Hope this helps!</span>

4 0

3 years ago

What specific structures are in electroreceptors?

Slav-nsk [51]

Electroreception is limited to aquatic environments because on here is the resistivity of the medium is low enough for electric currents to be generated as the result of electric fields of biological origin. In air, the resistivity of the environment is so high that electric fields from biological sources do not generate a significant electric current. Electroreceptor are found in a number of species of fish, and in at least one species of mammal, the Duck-Billed platypus.

7 0

4 years ago

Two sites are being considered for wind power generation. In the first site, the wind blows steadily at 7 m/s for 3000 hours per

slavikrds [6]

Answer:

E.year₂ > E.year₁ (Second site is better)

Explanation:

Given data

$V_{1}=7 m/s\\Time_{1}=3000 hours/year\\V_{2}=10m/s\\Time_{2}=1500hours/year$

The power generation is the time rate of kinetic energy which can be calculated as:

Power=ΔKE=m×V²/2

Regarding that m ∝ V.Then

Power ∝ V³ ⇒ Power=constant×V³

Since ρa is constant for both sides and Area is the same as same wind turbine is used

For First site

$Power_{1}=const.V^3\\Power_{1}=const.(7m/s)^3\\Power_{1}=const.343Watt\\$

For second site

$Power_{2}=const.V_{2}^3\\Power_{2}=const.(10m/s)^3\\Power_{2}=const.1000W$

Calculating energy generation per year for each of two sites

E.year=Power×Operation time per year

For First site

E.year₁=Power₁×Operation time₁ per year

$E_{year1}=const.*343W*3000\\E_{year1}=const.1029000(W.hour/year)$

For Second site

E.year₂=Power₂×Operation time₂ per year

$E_{year2}=const.*1000W*1500\\E_{year2}=const.1500000(W.hour/year)$

So

E.year₂ > E.year₁ (Second site is better)

3 0

4 years ago

Read 2 more answers

A ball is thrown upwards at 20m/s what is its displacement from its starting position at 7 seconds

Gre4nikov [31]

Two hundred 432000 was broke down into aalll these parts

3 0

4 years ago

A ray of monochromatic light ( f = 5.09 × 10^14 Hz) passes from air into Lucite at an angle

harina [27]

Let us consider the air with the index 1 and the lucite with index 2. Using the Snell's Secound Law, we have:

$\frac{sen\O_{2}}{sen\O_{1}} = \frac{n_{2}}{n_{1}} \\ sen\O_{2}= \frac{n_{2}*sen\O_{1}}{n_{1}}$

Entering the unknowns, remembering that the air refrective index is 1 and the lucite refrective index is 1.5, comes:

$sen\O_{2}= \frac{n_{2}*sen\O_{1}}{n_{1}} \\ sen\O_{2}= \frac{1.5* \frac{1}{2} }{1} \\ sen\O_{2}=0.75$

Using the arcsin properties, we get:

$sen\O_{2}=0.75 \\ arcsin(0.75)=\O_{2} \\ \boxed {\O_{2}=48.59^o}$

Obs: Approximate results, and the drawing is attached

If you notice any mistake in my english, let me know, because i am not native.

6 0

3 years ago