answer d. down hill schussing
Explanation:
I took the quiz
Explanation:
It is given that,
Potential difference between the ends of a rod, V = 1.1 V
Length of the rod, l = 10 cm = 0.1 m
Area of cross section of the rod, 
The resistivity of graphite, 
(a) Let R is the resistance of the rod. It is given by :



So, the resistance of the rod is 0.833 ohms.
(b) Let I is the current flowing in the wire. It can be calculated using the Ohm's law as :


I = 1.32 A
(c) Let E is the electric field inside the rod. The electric field in terms of potential difference is given by :


E = 11 V/m
Hence, this is the required solution.
Answer:
<h3>
a)</h3>




<u>=> R= 6 Ohms(Ω)</u>
<h3>b)</h3>

<em>these lights operate at the usual 240 volts direct from the main electricity supply. Therefore,</em>

<em>R and 100 can interchange places</em>


<u>=> R = 576 Ω</u>
<u></u>
By Ohm's Law:

=> 240 = I × 576
=>
=> I = 0.417 A
<h3 /><h3>c)</h3>
I don't know it's resistance,... so sorry
<h3>d)</h3>
The brightness of the bulb in series is <em><u>less than</u></em> when they're placed individually.
For bulbs in series their resistance gets added to form the equivalent resistance of the two bulbs.
Their resistances are nothing but mere numbers and the sum of two numbers(positive of course) is greater than the numbers.
So, the effective resistance of some bulbs in series <u>is more</u> than the individual resistance.
And
<em>Brightness, i. e., Power</em>

If resistance increases, Power decreases.
Here, the effective resistance was for sure larger, therefore resistance was increasing, hence power decreased taking brightness along with it.
Answer:
His first law states that every object will remain at rest or in uniform motion in a straight line unless compelled to change its state by the action of an external force. In other words its inertia.
Explanation: