All categories

3 years ago

A spring stores 12 J when it is stretched by 16 cm. Calculate the spring constant.

Physics

1 answer:

Effectus [21]3 years ago

3 0

16cm=1.6m

$\\ \rm\rightarrowtail W=Fx$

$\\ \rm\rightarrowtail 12=1.6F$

$\\ \rm\rightarrowtail F=7.5N$

Now

$\\ \rm\rightarrowtail F=-Kx$

$\\ \rm\rightarrowtail 7.5=-1.6k$

$\\ \rm\rightarrowtail k=-4.68N/m$

You might be interested in

Which of the following is described here? "Point your skis straight down the fall line with your skis parallel and about a foot

elena55 [62]

answer d. down hill schussing

Explanation:

I took the quiz

3 0

3 years ago

Read 2 more answers

There is a potential difference of 1.1 V between the ends of a 10 cm long graphite rod that has a cross-sectional area of 0.90 m

Serga [27]

Explanation:

It is given that,

Potential difference between the ends of a rod, V = 1.1 V

Length of the rod, l = 10 cm = 0.1 m

Area of cross section of the rod, $A=0.9\ mm^2=9\times 10^{-7}\ m^2$

The resistivity of graphite, $\rho=7.5\times 10^{-6}\ \Omega-m$

(a) Let R is the resistance of the rod. It is given by :

$R=\rho \dfrac{l}{A}$

$R=7.5\times 10^{-6}\times \dfrac{0.1}{9\times 10^{-7}}$

$R=0.833\ \Omega$

So, the resistance of the rod is 0.833 ohms.

(b) Let I is the current flowing in the wire. It can be calculated using the Ohm's law as :

$I=\dfrac{V}{R}$

$I=\dfrac{1.1\ V}{0.833\ \Omega}$

I = 1.32 A

(c) Let E is the electric field inside the rod. The electric field in terms of potential difference is given by :

$E=\dfrac{V}{l}$

$E=\dfrac{1.1\ V}{0.1\ m}$

E = 11 V/m

Hence, this is the required solution.

8 0

3 years ago

I NEED HELP ASAP! BRAINIEST TO THE CORRECT ANSWER. HELP ME NOW!

sergij07 [2.7K]

Answer:

$\boxed{\mathfrak{Power(P)=\frac{Voltage(V)^2}{Resistance(R)} }}$

V = 12 V
P = 24 W

$\implies \mathsf{24=\frac{12^2}{R} }$

$\implies \mathsf{24R=12^2 }$

$\implies \mathsf{24R=144 }$

$\boxed{\mathfrak{Power(P)=\frac{Voltage(V)^2}{Resistance(R)} }}$

Power (P)= 100 W

<em>these lights operate at the usual 240 volts direct from the main electricity supply. Therefore,</em>

V = 240 V

$\implies \mathsf{100=\frac{240^2}{R} }$

<em>R and 100 can interchange places</em>

$\implies \mathsf{R=\frac{240^2}{100} }$

$\implies \mathsf{R=\frac{57600}{100} }$

<u></u>

By Ohm's Law:

$\boxed{\mathsf{Voltage(V)=Current(I) \times Resistance(R)}}$

=> 240 = I × 576

=> I = 0.417 A

I don't know it's resistance,... so sorry

The brightness of the bulb in series is <em><u>less than</u></em> when they're placed individually.

For bulbs in series their resistance gets added to form the equivalent resistance of the two bulbs.

Their resistances are nothing but mere numbers and the sum of two numbers(positive of course) is greater than the numbers.

So, the effective resistance of some bulbs in series <u>is more</u> than the individual resistance.

And

<em>Brightness, i. e., Power</em>

$\boxed{\mathfrak{Power \propto \frac{1}{Resistance} }}$

If resistance increases, Power decreases.

Here, the effective resistance was for sure larger, therefore resistance was increasing, hence power decreased taking brightness along with it.

3 0

3 years ago

Isaac Newton's first law of motion states?

lesya [120]

Answer:

His first law states that every object will remain at rest or in uniform motion in a straight line unless compelled to change its state by the action of an external force. In other words its inertia.

Explanation:

8 0

3 years ago

A book is sitting on a table. jackie is pushing the book with a force of 9 N to the right. if the force of friction is 4 N to th

laila [671]

Answer:

Explanation:

4+5 =9

5n to the right

4 0

3 years ago

Read 2 more answers