Answer:
c) Water molecules melt into gas molecules.
Answer:
A-Caclcuate the potential energy of the ball at that height
Explanation:
(a). Mass of the Body = 10 kg.
Height = 10 m.
Acceleration due to gravity = 9.8 m/s².
Using the Formula,Potential Energy = mgh
= 10 × 9.8 × 10 = 980 J.
(b). Now, By the law of the conservation of the Energy, Total amount of the energy of the system remains constant.
∴ Kinetic Energy before the body reaches the ground is equal to the Potential Energy at the height of 10 m.
∴ Kinetic Energy = 980 J.
(c). Kinetic Energy = 980 J.
Mass of the ball = 10 kg.
∵ K.E. = 1/2 × mv²
∴ 980 = 1/2 × 10 × v²
∴ v² = 980/5
⇒ v² = 196
∴ v = 14 m/s.
Answer:
Explanation:
Kinetic energy of ball in motion = 1/2 m v² . Potential energy = 0
Let the minimum distance between the balls be d on collision.
Electric potential energy at that time= k Q²/d , Here kinetic energy is converted into potential energy . So
1/2 m v² = kQ²/d
d =2 k Q² / mv²,= 18 x 10⁹ x Q²/ m v².