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3 years ago

8 points

Physics

2 answers:

Simora [160]3 years ago

6 0

The pilot is correct because of gravity

Lunna [17]3 years ago

4 0

The pilot might be correct (I think), because, if the gravity of the planet is strong, then the planet’s gravity will pull the spaceship into its orbit, so the engines don’t need to be on for the ship to get pushed toward the planet.

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__________, the best forecasting methods to use are time series models such as moving average. ANSWER Unselected When the future

DochEvi [55]

Answer:

Greetings!

The correct answer is the last one, "When the future level of some variable is seen as a function other than time".

Explanation:

Along other forecasting methods, the moving average finds utility in cases when seasonality is a factor. This term refers to a set of variables unknown to (or uncontrolled by) the observer that influence the series model in some way.

By applying a moving average to a time series one can mitigate such irregular effects.

I hope this helps!

8 0

3 years ago

A true hero is the unifying force in the diverse society

Eduardwww [97]

This indeed is true, a hero is someone who can against very bad odds unify a country that can be torn or just be generally very heterogenous. There have been many cases of such heroes in the past where they would unify a certain country or society under the same banner.

4 0

3 years ago

Donuts are a simple or complex carbohydrate? *<br> Ok

zubka84 [21]

Answer:

simple carbohydrate

Explanation:

Simple carbs are like cakes, donuts, and candy, etc.

Hope this helps :D

6 0

3 years ago

In a photoelectric experiment it is found that a stopping potential of 1.00 V is needed to stop all the electrons when incident

kiruha [24]

Answer:

Planck’s constant is $6.9*10^{-34} Js$

work function of metal is $5.846*10^{-19}$

Explanation:

The maximum kinetic energy from electron from photoelectric effect is given by

$\K_{max}=eV_o$ where $V_o$ is applied voltage and e is charge on electron and substituting charge on electron by $1.6*10^{-19}$ and 1.00 V for $V_o$

$K_{max}=1.6*10^{-19}*1=1.6*10^{-19} J$

Considering that the wavelength, \lambda of light used is given as $278*10^{-9} m$

Energy of light is given by

$E=\frac {hc}{ \lambda}$ where $\lambda$ is the wavelength, h is Planck’s constant and c is speed of light. Taking c for $3*10^{8} m/s$

Substituting values of wavelength and speed of light we obtain

$E=\frac {h*3*10^{8}}{278*10^{-9}}=h1.07914*10^{15} J$

If work function is $\phi$ then

$E=\phi + k_{max}$ hence

$h1.07914*10^{15} J=\phi +1.6*10^{-19} J$ ------- Equation 1

Energy corresponding to wavelength of 207 nm is

$E=h\frac {3*10^{8} m/s}{207*10^{-9}}=h(1.45*10^{15}}) J$

Maximum kinetic energy of electrons when $V_o$ is 2.6 V becomes

$K_{max}=(1.6*10^{-19})*2.6V=4.16*10^{-19} J$

From $E=\phi + k_{max}$ and substituting $h(1.45*10^{15}}) J$ for E and $4.16*10^{-19} J$ for $K_{max}$ we have

$h(1.45*10^{15}}) J=\phi +4.16*10^{-19} J$ ------ Equation 2

Equation 2 minus equation 1 gives

$h3.71*10^{14}=2.56*10^{-19}$

$h=\frac {2.56*10^{-19}}{3.71*10^{14}}\approx 6.9*10^{-34} Js$

Therefore, Planck’s constant is $6.9*10^{-34} Js$

Recalling equation 1 and substituting back the value of h as obtained

$h1.07914*10^{15} J=\phi +1.6*10^{-19} J$

$(6.9*10^{-34})*(1.07914*10^{15})=\phi +1.6*10^{-19} J$

$\ph=(6.9*10^{-34})*(1.07914*10^{15})-(1.6*10^{-19})=5.846*10^{-19}$

Therefore, work function of metal is $5.846*10^{-19}$

5 0

4 years ago

A highway patrolman traveling at the speed limit is passed by a car going 20 mph faster than the speed limit. After one minute,

Oksi-84 [34.3K]

Answer:

It will take 40 seconds to catch the speeding car

Explanation:

Initial speed of the patrolman = 55 mph

after one minute speed of patrol man = 115 mph

now acceleration of patrolman is given by

$a = \frac{v_f - v_i}{t}$

$a = \frac{115 - 55}{1/60} = 3600 m/h^2$

now at this acceleration the distance covered by patrolman in "t" time is given as

$d = v_i t + \frac{1}{2}at^2$

$d = 55t + 1800t^2$

now we know the speed of the speeding car is given as

$v' = (55+20) mph$

now in the same time distance covered by it

$d = 75 t$

now since the distance covered is same

$75 t = 55t + 1800 t^2$

$t = \frac{20}{1800} = \frac{1}{90} h$

$t = 40 seconds$

7 0

4 years ago

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