<span>pKb = - log 1.8 x 10^-5 = 4.7
moles NH3 = 0.0750 L x 0.200 M=0.0150
moles HNO3 = 0.0270 L x 0.500 M= 0.0135
the net reaction is
NH3 + H+ = NH4+
moles NH3 in excess = 0.0150 - 0.0135 =0.0015
moles NH4+ formed = 0.0135
total volume = 75.0 + 27.0 = 102.0 mL = 0.102 L
[NH3]= 0.0015/ 0.102 L=0.0147 M
[NH4+] = 0.0135/ 0.102 L = 0.132 M
pOH = pKb + log [NH4+]/ [NH3]= 4.7 + log 0.132/ 0.0147=5.65
pH = 14 - pOH = 14 - 5.65 =8.35
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<h3>
Answer: 1.6 mol (option 5)</h3>
Explanation:
<u>Mole Ratio of O₂ : NO</u>
Based on the balanced equation, the mole ratio of O₂ : NO is 5 : 4
∴ for every mole of O₂ reacted, ⁴/₅ moles of NO is produced
<u>Moles of NO</u>
since the number of mol of O₂ = 2.0 mol
then moles of NO produced = 2.0 mol × ⁴/₅
= 1.6 mol
∴ the moles of nitrogen monoxide that will form if we start with 2.0 moles of oxygen is 1.6 mol (option 5).
Answer:
B-Fluorine
Explanation:
Fluorine is a non metal, and these tend tp form anions, compared to their metal cation counterparts.
Your answer would be 637.25g