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kap26 [50]
3 years ago
7

How many grams of aluminum oxide would form if 15.2 moles of aluminum burned

Chemistry
1 answer:
Step2247 [10]3 years ago
4 0

Your answer would be 637.25g

You might be interested in
A nitrox ii gas mixture for scuba diving contains oxygen gas at 53 atm and nitrogen gas at 94 atm . what is the total pressure,
Alina [70]

Answer: The total pressure will be 1,11,720 torr.

Explanation:

Partial pressure of nitrogen gas.p_{N_2}=53 atm=53\times 760 torr= 40,280 torr (1atm = 760 torr)

Partial pressure of oxygen gas,p_{O_2}=94 atm=94\times 760 torr=71,440 torr

Total pressure, in torrs, of the scuba gas mixture = 40280 + 71440 torr =111,720 torr

Hence , the total pressure in scuba gas mixture is 111,720 torr.

6 0
3 years ago
What mass of Sodium Chloride is required to make 100.0 mL of 3.0 M solution?
Julli [10]

Answer:

17.55 g of NaCl

Explanation:

The following data were obtained from the question:

Molarity = 3 M

Volume = 100.0 mL

Mass of NaCl =..?

Next, we shall convert 100.0 mL to L. This can be obtained as follow:

1000 mL = 1 L

Therefore,

100 mL = 100/1000

100 mL = 0.1 L

Therefore, 100 mL is equivalent to 0.1 L.

Next, we shall determine the number of mole NaCl in the solution. This can be obtained as follow:

Molarity = 3 M

Volume = 0.1 L

Mole of NaCl =?

Molarity = mole /Volume

3 = mole of NaCl /0.1

Cross multiply

Mole of NaCl = 3 × 0.1

Mole of NaCl = 0.3 mole

Finally, we determine the mass of NaCl required to prepare the solution as follow:

Mole of NaCl = 0.3 mole

Molar mass of NaCl = 23 + 35.5 = 58.5 g/mol

Mass of NaCl =?

Mole = mass /Molar mass

0.3 = mass of NaCl /58.5

Cross multiply

Mass of NaCl = 0.3 × 58.5

Mass of NaCl = 17.55 g

Therefore, 17.55 g of NaCl is needed to prepare the solution.

5 0
3 years ago
How many atoms of Ga are there?
xz_007 [3.2K]
The answer is 2

Hope this helped ??
5 0
2 years ago
4. What is the percent by mass of tungsten in the calcium tungstate compound CaWO3, commonly
MA_775_DIABLO [31]

Answer: 67.4%

Explanation:

Ca 40.8

W. 183.8

O. 16.00

CaWO3 272.6

W = 183.8/272.6 = 0.674

3 0
3 years ago
Give the n and l values and the number of orbitals for sublevel 5g.
Pepsi [2]

The n and l values and the number of orbitals for sublevel 5g is :

5g shell , n= 5 subshell g , l = 4, Number of orbitals for sublevel = 9.

There are total four quantum numbers:

1) Principal quantum number , n

2) Angular quantum number , l

3) Magnetic quantum number , ml

4) spin quantum number , ms

For 5g shell, n = 5

subshell g , l = 4     ....0 - s , 1 - p , 2 - d, 3 - f, 4 -g

number of orbitals in subshell = (2l + 1)  ( 2×4 + 1) = 9

Thus,  The n and l values and the number of orbitals for sublevel 5g is :

5g shell , n= 5 subshell g , l = 4, Number of orbitals for sublevel = 9.

To learn more about quantum numbers here

brainly.com/question/14650894

#SPJ1

6 0
11 months ago
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