Hey there! :D
Look at the word hydrolysis. Hydro= water Lysis = split. (Root words)
So, water (in terms of the word) is added to help split and breakdown macromolecules.
I hope this helps!
~kaikers
Missing data in your question: (please check the attached photo)
from this balanced equation:
M(OH)2(s) ↔ M2+(aq) + 2OH-(aq) and when we have Ksp = 2x10^-16
∴Ksp = [M2+][OH]^2
2x10^-16 = [M2+][OH]^2
a) SO at PH = 7 ∴POH = 14-PH = 14- 7 = 7
when POH = -㏒[OH]
7= -㏒[OH]
∴[OH] = 1x10^-7 m by substitution with this value in the Ksp formula,
∴[M2+] =Ksp /[OH]^2
= (2x10^-16)/(1x10^-7)^2
= 0.02 M
b) at PH =10when POH = 14- PH = 14-10 = 4
when POH = -㏒[OH-]
4 = -㏒[OH-]
∴[OH] = 1x10^-4 ,by substitution with this value in the Ksp formula
[M2+] = Ksp/ [OH]^2
= 2x10^-16 / (1x10^-4)^2
= 2x10^-8 Mc) at PH= 14
when POH = 14-PH
= 14 - 14
= 0
when POH = -㏒[OH]
0 = - ㏒[OH]
∴[OH] = 1 m
by substitution with this value in Ksp formula :
[M2+] = Ksp / [OH]^2
= (2x10^-16) / 1^2
= 2x10^-16 M
Answer:
Cyanide
Explanation:
<em>Molecular Structure of Each Answer</em>
A: CN-
B: NO3-
C: OH-
D: SO4 2-
As you can see, only A (Cyanide) is the only compound that does not contain oxygen, meaning it is NOT an oxyanion.
Answer:
0.1357 M
Explanation:
(a) The balanced reaction is shown below as:

(b) Moles of
can be calculated as:
Or,
Given :
For
:
Molarity = 0.1450 M
Volume = 10.00 mL
The conversion of mL to L is shown below:
1 mL = 10⁻³ L
Thus, volume = 10×10⁻³ L
Thus, moles of
:
Moles of
= 0.00145 moles
From the reaction,
1 mole of
react with 2 moles of NaOH
0.00145 mole of
react with 2*0.00145 mole of NaOH
Moles of NaOH = 0.0029 moles
Volume = 21.37 mL = 21.37×10⁻³ L
Molarity = Moles / Volume = 0.0029 / 21.37×10⁻³ M = 0.1357 M
Answer:
Answer is D.Blue.
Explanation:
The hottest stars tend to appear blue or blue-white, whereas the coolest stars are red.
I hope it's helpful!