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Alja [10]
2 years ago
12

Q= r/2 (s +t) for t.

Mathematics
1 answer:
Vanyuwa [196]2 years ago
7 0

Answer:

t=2Q-sr/r

Step-by-step explanation:

We are to make t the subject of formula from the given question

Q=r/2 (s+t)

Q=Sr+tr/2

Cross multiply

2Q=Sr+tr

2Q-sr=tr

t=2Q-sr/r

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Answer:

See below

Step-by-step explanation:

Use the formulae directly

For a cone, with base radius = r and height = h, here are the related formula

\textrm{Slant height  l} = \sqrt{r^2 + h^2}  (1)

\textrm{Lateral surface area} = \pi r l

\textrm {Base area} = \pi r^2

\textrm { Total Surface Area SA} = \textrm{Base Area + Lateral Area} = \pi r^2 + \pi rl = \pi r(r + l) (2)

\textrm{Volume V = } (1/3)  \pi r^2h (3)

Therefore directly plugging in the numbers in the above equations:

Note:

l = slant height in cm
SA = total surface area in sqcm
V = Volume in cubic cm

Figure(a)

r = 4, h = 8

\textrm{l} = \sqrt{4^2 + 8^2} =\sqrt{80} = 8.944 \\\textrm{SA}  = 4\pi(4 + 8.944) =  4\pi(12.944) = 162.66\\\textrm{V} = (1/3)\pi(4^2)(8) = 134.04

Figure(b)

r = 7, h =15

\textrm{l} = \sqrt{7^2 + 15^2} =\sqrt{274} = 16.55

\textrm{SA}  = 7\pi(7 + 16.55) =  517.89

Figure (c)

r = 5, l = 8

h = \sqrt{l^2 - r^2} = \sqrt{8^2 - 5^2} = \sqrt{39} = 6.245\\SA = \textrm{SA}  = 5\pi(5 + 8) =  204.2\\V = (1/3)\pi(5^2)(6.245) = 163.5


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