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ollegr [7]
3 years ago
14

When using available remote engine start, what factors affect how 2022 titan’s intelligent climate control system initiates clim

ate control temperature, fan speed, and air circulation mode?.
Engineering
1 answer:
Elodia [21]3 years ago
7 0

An ambient temperature and factory programming are the factor that could affect how the control system could initiates climate control temperature, fan speed etc.

<h3>What is an intelligent climate control system?</h3>

An intelligent climate control system is a vehicle system that control the temperature levels in the vehicle' spaces

In conclusion, the control system are more likely to be affected by ambient temperature and factory programming

Read more about control system

<em>brainly.com/question/14878948</em>

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De acuerdo con el tabulador de puestos de una compañía, los salarios mensuales que obtienen los trabajadores son los que se mues
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Sorry don’t understand
8 0
3 years ago
A car accelerates from rest with an acceleration of 5 m/s^2. The acceleration decreases linearly with time to zero in 15 s, afte
Tpy6a [65]

Answer: At time 18.33 seconds it will have moved 500 meters.

Explanation:

Since the acceleration of the car is a linear function of time it can be written as a function of time as

a(t)=5(1-\frac{t}{15})

a=\frac{d^{2}x}{dt^{2}}\\\\\therefore \frac{d^{2}x}{dt^{2}}=5(1-\frac{t}{15})

Integrating both sides we get

\int \frac{d^{2}x}{dt^{2}}dt=\int 5(1-\frac{t}{15})dt\\\\\frac{dx}{dt}=v=5t-\frac{5t^{2}}{30}+c

Now since car starts from rest thus at time t = 0 ; v=0 thus c=0

again integrating with respect to time we get

\int \frac{dx}{dt}dt=\int (5t-\frac{5t^{2}}{30})dt\\\\x(t)=\frac{5t^{2}}{2}-\frac{5t^{3}}{90}+D

Now let us assume that car starts from origin thus D=0

thus in the first 15 seconds it covers a distance of

x(15)=2.5\times 15^{2}-\farc{15^{3}}{18}=375m

Thus the remaining 125 meters will be covered with a constant speed of

v(15)=5\times 15-\frac{15^{2}}{6}=37.5m/s

in time equalling t_{2}=\frac{125}{37.5}=3.33seconds

Thus the total time it requires equals 15+3.33 seconds

t=18.33 seconds

3 0
3 years ago
Please calculate the energy stored in a flying wheel. The steel flying wheel is 10 metric tons, in adiameter of 10m, and it rota
Liono4ka [1.6K]

Answer:

685.38 MJ

Explanation:

Given that:

mass = 10 tons = 1.0 × 10 ⁴ kg

diameter D = 10 m

radius R = 5 m

speed N = 1000 rpm

Using the formula for K.E = \dfrac{1}{2}I \omega^2 to calculate the energy stored

where;

= \dfrac{2 \pi \times N}{60}

= \dfrac{2 \pi \times 1000}{60}

= 104.719 rad/s

Hence, the energy stored is;

= \dfrac{1}{2}\times (\dfrac{MR^2}{2}) \times \omega^2

= \dfrac{1}{2}\times (\dfrac{10^4\times 5^2}{2}) \times 104.719^2

= 685379310.1

= 685.38 MJ

8 0
3 years ago
What is the density of a 3.25 in. diameter sphere of steel that weighs 3.21 lbs?
hjlf

Answer: 308.602944277163 lb/ft cubed

8 0
3 years ago
A process fluid having a specific heat of 3500 J/kg-K and flowing at 2 kg/s is to be cooled from 80 C to 50 C with chilled water
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Answer:

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Explanation:

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