Question

Please calculate the energy stored in a flying wheel. The steel flying wheel is 10 metric tons, in adiameter of 10m, and it rotates at a speed of 1000 rpm. The steel density is 8050 kg/m^3. When energyis fully released, the flying wheel stops its rotation.

Answer 1

Answer:

685.38 MJ

Explanation:

Given that:

mass = 10 tons = 1.0 × 10 ⁴ kg

diameter D = 10 m

radius R = 5 m

speed N = 1000 rpm

Using the formula for K.E = $\dfrac{1}{2}I \omega^2$ to calculate the energy stored

where;

$= \dfrac{2 \pi \times N}{60}$

$= \dfrac{2 \pi \times 1000}{60}$

= 104.719 rad/s

Hence, the energy stored is;

$= \dfrac{1}{2}\times (\dfrac{MR^2}{2}) \times \omega^2$

$= \dfrac{1}{2}\times (\dfrac{10^4\times 5^2}{2}) \times 104.719^2$

= 685379310.1

= 685.38 MJ