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3 years ago

Weight limit for a pallet

Engineering

2 answers:

hammer [34]3 years ago

6 0

Answer:

standard pallet can withstand 4,600lbs

Explanation:

Grace [21]3 years ago

5 0

4,600 pounds I believe

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Which task best fits the role of a planning engineer?

Nonamiya [84]

Answer:

Explanation:

ensuring project end on time through carefully planning and organizing

8 0

3 years ago

Is the COP of a heat pump always larger than 1?

Liono4ka [1.6K]

Answer:

Yes

Explanation:

Yes it is true that COP of heat pump always greater than 1.But the COP of refrigeration can be greater or less than 1.

We know that

COP of heat pump= 1 + COP of refrigeration

It is clear that COP can not be negative .So from the above expression we can say that COP of heat pump is always greater than one.

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3 years ago

What is the metal removal rate when a 2 in-diameter hole 3.5 in deep is drilled in 1020 steel at cutting speed of 120 fpm with a

Studentka2010 [4]

Answer:

a) the metal removal rate is 14.4 in³/min

b) the cutting time is 0.98 min

Explanation:

Given the data from the question

first we find the rpm for the spindle of the drilling tool, using the equation

Ns = 12V/πD

V is the cutting speed(120 fpm) and D is the diameter of the hole( 2 in)

so we substitute

Ns = 12 × 120 / π2

Ns = 1440 / 6.2831

Ns = 229.18 rmp

Now we find the metal removal rate using the equation

MRR = (πD²/4) Fr × Ns

Fr is the feed rate( 0.02 ipr ),

so we substitute

MRR = ((π × 2²)/4) × 0.02 × 229.18

MRR = 14.3998 ≈ 14.4 in³/min

Therefore the metal removal rate is 14.4 in³/min

Next we find the allowance for approach of the tip of the drill

A = D/2

A = 2/2

= 1 in

now find the time required to drill the hole

Tm = (L + A) / (Fr × Ns)

Lis the the depth of the hole( 3.5 in)

so we substitute our values

Tm = (3.5 + 1) / (0.02 × 229.18 )

Tm = 4.5 / 4.5836

Tm = 0.98 min

Therefore the cutting time is 0.98 min

8 0

2 years ago

What is the definition of a duty cycle?

ira [324]

Answer:

$D=\frac{PW}{T}*100$

Explanation:

In electrical terms, is the ratio of time in which a load or circuit is ON compared to the time in which the load or circuit is OFF.

The duty cycle or power cycle, is expressed as a percentage of the activation time. For example, a 70% duty cycle is a signal that 70% of the time is activated and the other 30% disabled. Its equation can be expressed as:

$D=\frac{PW}{T}*100$

Where:

$D=Duty\hspace{3}Cycle$

$PW=Pulse\hspace{3}Active\hspace{3}Time$

$T=Period\hspace{3}of\hspace{3}the\hspace{3}Signal$

Here is a picture that will help you understand these concepts.

5 0

3 years ago

Two thousand pieces will flow through from the first machine A to the final machine F based on the given sequence of operations.

Vlad1618 [11]

The total number of trips that the vehicle has to make based on the given sequence of operation is 120 trips.

"Your question is not complete, it seems to be missing the following information;"

The sequence of operation is A - E - D - C - B - A - F

The given parameters;

number of pieces that will flow from the first machine A to machine F, = 2,000 pieces
initial unit load specified in the first machine, L₁ = 50
final unit load, L₂ = 100
the capacity of the vehicle = 1 unit load

The given sequence of operation of the vehicle;

A - E - D - C - B - A - F

the vehicle makes 6 trips for 100 unit loads

The total number of trips that the vehicle has to make, in order to transport the 2000 pieces of the load given, is calculated as follows.

100 unit loads ----------------- 6 trips

2000 unit loads --------------- ?

$= \frac{2000}{100} \times 6\\\\= 120 \ trips$

Thus, the total number of trips that the vehicle has to make based on the given sequence of operation is 120 trips.

Learn more here:brainly.com/question/21468592

6 0

2 years ago