Question

Find the value of x in the equation: x^2 + 4 = 12

Answer 1

Answer:

$\sqrt{8} = 2 \sqrt{2}$

Step-by-step explanation:

In the equation we must first move 4 to the other side and change its sign

x^2 + 4 = 12

x^2 = 12 - 4

x^2 = 8

Then we find x:

x =

$x = \sqrt{8} = \sqrt{2 \times 2 \times 2} = \sqrt{ {2}^{2} \times 2 } = 2 \sqrt{2}$