Answer:
C' will be located at (-4,-2)
Step-by-step explanation:
The first five terms of the sequence are 1, 4, 7, 10, 13.
Solution:
Given data:


General term of the arithmetic sequence.
, where d is the common difference.
d = 3

Put n = 2 in
, we get



Put n = 3 in
, we get



Put n = 4 in
, we get



Put n = 5 in
, we get



The first five terms of the sequence are 1, 4, 7, 10, 13.
Answer:
The minimum weight for a passenger who outweighs at least 90% of the other passengers is 203.16 pounds
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

What is the minimum weight for a passenger who outweighs at least 90% of the other passengers?
90th percentile
The 90th percentile is X when Z has a pvalue of 0.9. So it is X when Z = 1.28. So




The minimum weight for a passenger who outweighs at least 90% of the other passengers is 203.16 pounds