Hello!
Recall that:
![\sqrt[z]{x^{y} }](https://tex.z-dn.net/?f=%5Csqrt%5Bz%5D%7Bx%5E%7By%7D%20%7D)
is equal to 
. Therefore:
![\sqrt[3]{x^{2} } = x^{\frac{2}{3} }](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E%7B2%7D%20%7D%20%3D%20x%5E%7B%5Cfrac%7B2%7D%7B3%7D%20%7D)
There is also an exponent of '6' outside. According to exponential properties, when an exponent is within an exponent, you multiply them together. Therefore:
so if 5.5 is in meter let change it to cm because the question want us to give the answer in cm.
now we multiply 5.5 times 100 which is equal to 550.
next we subtract 550 - 220= 330.
finally, the difference between a teacher and student is 330cm .meaning the teacher's desk is 330 cm longer or taller than the student.
This question boils down to this:
"What is the diagonal of a square with a side length of 90 ft?"
The key to this question is the properties of squares.
All of the angles in a square are right, (90°) but that diagonal is going to bisect two of those into 45° angles.
Now we have two triangles, each with angle measures of 45°, 45°. and 90°.
(an isoceles right triangle)
This 45-45-90 tirnalge is one of two special triangles (the other being the 30-60-90) and here is its special property: the sides opposite these angles can be put as x, x, and x√2 respectively. Why? Well, we know that our triangle is isoceles (the congruent base angles ⇔ congruent sides) and so we call those x...by the Pythagorean theorem...a² + b² = c²...2x² = c²...x√2 = c!
In our case here, that diagonal, being the hypotenuse of our triangle, is going to be 90√2 feet, or approximately 127.3 feet.
<span>42 in is 3/4th of 56 in. </span>
<span>3/4th of 24 in. is 18 in. </span>
<span>The length of his friend's shadow at the same time is </span>
<span>b.) 18 in.</span>
