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alex41 [277]
2 years ago
7

PLZZZZZ HELPP How do you predict the bond length and energy would change if hydrogen formed a bond with Astatine (At)? ​

Chemistry
1 answer:
kkurt [141]2 years ago
6 0

The bond length and energy of the bond formed between hydrogen (H) and astatine (At) would change if the bond order <u>increases</u> or <u>decreases</u> or when its potential energy is at the <u>lowest</u>.

<h3>What is bond length?</h3>

Bond length is also referred to as bond distance and it can be defined as an equilibrium distance between the nuclei of two (2) covalently bonded atoms in a molecule.

<h3>What is bond energy?</h3>

Bond energy can be defined as the amount of chemical energy that is required to break one mole of a given chemical bond.

In Chemistry, the bond length and energy of a molecule is typically determined by the following:

  • The bond order or number of bonded electrons.
  • The potential energy possessed by the molecule.

In conclusion, you can predict that the bond length and energy of the bond formed between hydrogen (H) and astatine (At) would change if the bond order increases or decreases or when its potential energy is at the lowest.

Read more on bond energy here: brainly.com/question/5650115

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Answer:

1. How many ATOMS of boron are present in 2.20 moles of boron trifluoride? atoms of boron.

2. How many MOLES of fluorine are present in  of boron trifluoride? moles of fluorine.​

Explanation:

The molecular formula of boron trifluoride is BF_3.

So, one mole of boron trifluoride has one mole of boron atoms.

1. The number of boron atoms in 2.20 moles of boron trifluoride is 2.20 moles.

The number of atoms in 2.20 moles of boron is:

One mole of boron has ---- 6.023x10^2^3 atoms.

Then, 2.20 moles of boron has

-=2.20 mol. x 6.023 x 10^2^3 atoms /1 mol\\=13.25x10^2^3 atoms

2. Calculate the number of moles of BF3 in 5.35*1022 molecules.

(5.35x10^2^2 molecules/6.023x10^2^3)x 1mol\\=0.0888mol

One mole of boron trifluoride has three moles of fluorine atoms.

Hence, 0.0888moles of BF3 has 3x0.0888mol of fluorine atoms.

=0.266mol of fluorine atoms.

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\mathfrak{\huge{\pink{\underline{\underline{AnSwEr:-}}}}}

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Since Sodium (Na) is a cation and Chlorine (Cl) is a Anion, they both form a Ionic bond called as NaCl (common salt)

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