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1 year ago

Simplify (3y^6)^5/(y^3)^5

Mathematics

2 answers:

Alex17521 [72]1 year ago

5 0

Answer: 245y^15

Step-by-step explanation:

otez555 [7]1 year ago

3 0

245y^15 that’s the correct answer I believe I’m not to positive

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HELPPP NEED IN THE NEXT 10 MINSSS!!!!

Mice21 [21]

Answer:

15.6

Step-by-step explanation:

the traingle is right so u have to apply the pythagorean theorem to find x so x^2=10^2+12^2=244

so x=15.6

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2 years ago

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Billy has $3.00. Bubble gum costs $.30. He bought four pieces.

xenn [34]

Answer:

$0.30 x 4= $1.20

$3.00 divided by $1.20= $1.80

Step-by-step explanation:

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3 years ago

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Geometry math question no Guessing and Please show work

tatyana61 [14]

The point where the two diagonals meet is also the midpoint of both diagonals.

This means that AE = EC . Since we have the value for both segments, we have

$AE = EC \implies 2x = x+2 \implies x = 2$

Since AC = AE + EC, we have

$AE + EC = 2x+x+2 = 3x+2 = 3\cdot 2 + 2 = 6+2 = 8$

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2 years ago

The expression (q16)(q−5)2 is equivalent to qn. What is the value of n? 42 22 -160 13

Lelu [443]

Answer:

Step-by-step explanation:

In order to get one of the answer choices, it appears we need to interpret your input as ...

$(q^{16}q^{-5})^2 = (q^{16-5})^2=q^{11\cdot 2}=q^{22}$

The value of n is 22.

The applicable rules of exponents are ...

(a^b)(a^c) = a^(b+c)

(a^b)^c = a^(bc)

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3 years ago

Find the area ratio of a regular octahedron and a tetrahedron regular, knowing that the diagonal of the octahedron is equal to h

Anton [14]

Answer:

$\frac{4}{3}$

Step-by-step explanation:

The area of a regular octahedron is given by:

area = $2\sqrt{3}\ *edge^2$ . Let a is the length of the edge (diagonal).

area = $2\sqrt{3}\ *a^2$

Given that the diagonal of the octahedron is equal to height (h) of the tetrahedron i.e.

a = h, where h is the height of the tetrahedron and a is the diagonal of the octahedron. Let the edge of the tetrrahedron be e. To find the edge of the tetrahedron, we use:

$h=\sqrt{\frac{2}{3} } e\\but\ h=a\\a=\sqrt{\frac{2}{3} } e\\e=\sqrt{\frac{3}{2} }a$

The area of a tetrahedron is given by:

area = $\sqrt{3}\ *edge^2$ = $\sqrt{3} *(\sqrt{\frac{3}{2} }a)^2=\frac{3}{2}\sqrt{3} *a^2$

The ratio of area of regular octahedron to area tetrahedron regular is given as:

Ratio = $\frac{2\sqrt{3}\ *a^2}{\frac{3}{2} \sqrt{3}*a^2} =\frac{4}{3}$

7 0

3 years ago