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Tcecarenko [31]
3 years ago
10

Please help! show in dept steps

Mathematics
1 answer:
rewona [7]3 years ago
5 0

Given:

54.1 \times  \sqrt{15.11}

To remove decimal, divide first equation by 10 and second equation by 100

=  >  \frac{541}{10} \times  \sqrt{ \frac{1511}{100}}

Now opening the root,

=  >  \frac{541}{10} \times  \frac{ \sqrt{1511} }{ \sqrt{100}}

=  >  \frac{541}{10} \times  \frac{ \sqrt{1511} }{ \sqrt{10^{2} }}

=  >  \frac{541}{10} \times  \frac{ \sqrt{1511} }{10}

=  >  \frac{54 \times  \sqrt{1511} }{10 \times 10}

=  >  \frac{541 \sqrt{1511} }{100}

Hence, the answer is \frac{541 \sqrt{1511} }{100}

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as you notice the term under the square root is b^2-4ac if it is postive then the equation clearly will have two real soultions if it is negative then the equation will have two imaginary soultion if it is zero then the the equation will have one soultion
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Linear equations : brainly.com/question/9994201

Keywords : graph, linear equation, intercepts, plot

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Hello!

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=9
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