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Tcecarenko [31]
2 years ago
10

Please help! show in dept steps

Mathematics
1 answer:
rewona [7]2 years ago
5 0

Given:

54.1 \times  \sqrt{15.11}

To remove decimal, divide first equation by 10 and second equation by 100

=  >  \frac{541}{10} \times  \sqrt{ \frac{1511}{100}}

Now opening the root,

=  >  \frac{541}{10} \times  \frac{ \sqrt{1511} }{ \sqrt{100}}

=  >  \frac{541}{10} \times  \frac{ \sqrt{1511} }{ \sqrt{10^{2} }}

=  >  \frac{541}{10} \times  \frac{ \sqrt{1511} }{10}

=  >  \frac{54 \times  \sqrt{1511} }{10 \times 10}

=  >  \frac{541 \sqrt{1511} }{100}

Hence, the answer is \frac{541 \sqrt{1511} }{100}

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∠ DBC = 3X+6
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∠ ABD and ∠ DBC are linear pairs
∴ ∠ ABD +∠ DBC = 180
∴ 5(2X+1) + 3X+6 =180
solve for x
∴ x = 13
∴∠ ABD = 5(2X+1) = 5(2*13+1) = 135
  ∠ DBC = 3x+6  = 3*13+6 = 45

∠ ABD  and ∠ EBC are vertical angles
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The <span>statements that are true:
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C.) x=13
E.)measure of angle EBC =135
F.) angle DBC and angle EBC are linear pairs </span>




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<span>Therefore, the triangles ABD and CDB are congruent by SAS</span>
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