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grandymaker [24]
2 years ago
13

an item is regularly priced at $45 it is on sale for 20% off the regular price how much in dollars is discounted from the regula

r price?​
Mathematics
1 answer:
Lera25 [3.4K]2 years ago
5 0

Answer:$36

Step-by-step explanation:

Regular price=$45

sale =20%

Formula for calculation of 20%

=(45*20)/100

=900/100

=9

$45-$9=$36

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Please help, solve for x. Due today and all I’ve gotten are links :(
Nookie1986 [14]

Answer:

I think it might be 0 im not to sure.

6 0
2 years ago
A team of scientist surveying a forest found that there were four oak trees for every 10 pine trees. If they counted 24 more pin
Ipatiy [6.2K]

Answer:

There are 16 Oak tree in the forest.

Step-by-step explanation:

Given: There are 4 Oak tree on every 10 pine trees.

           There are total 24 more pine tree than Oak tree.

 Using the ratio of trees to find the number of trees.

Lets assume there are total number of Oak tree be "x".

∴ Total number of Pine trees will be "x+24"

We know the ratio of Oak to Pine tree is 4:10 or \frac{4}{10}

⇒\frac{x}{x+24} = \frac{4}{10}

Multiplying both side by x+24

⇒ x= \frac{4(x+24)}{10}

Using distributive property of multiplication, distributing 4 with x and 24.

⇒ x= \frac{4x+96}{10}

Multiplying both side by 10

⇒ 10x= 4x+96

subtracting both side by 4x

⇒ 6x= 96

dividing both side by 6

⇒x= \frac{96}{6}

∴ x= 16

Hence, There are 16 Oak trees in the forest.

5 0
3 years ago
Can someone please help me​
astra-53 [7]

Answer:

square 20 has 44 green squares

square 21 has 45 green squares

Step-by-step explanation:

To solve the problem, we need to observe the cases, and determine/define a rule for each case (odd number of sides, or even number of sides).

For square one, we note that the centre square is shared by two diagonals, so we saved one square from the two diagonals.

The side length is 3 for square 1, 4 for square 2, and so on.

Let

n= square number (1, 2,3...)

L = side length (3,4,5...)

G1(n) = function that gives the number of green squares for square n, n=odd

G2(n) = function that gives the number of green squares for square n, n=even

side length, L=n+2   ................(1)

G1(n) = twice the side length less one, as discussed above

G1(n) = 2L-1       now substitute L=n+2

G1(n) = 2(n+2) -1    simplify

G1(n) = 2n + 3

Check:

for n=1, square 1 has 2*1+3 = 5 green squares ... checks

for n=3, square 3 has 2*3+3 = 9... checks

for n=5, square 5 has 2*5+3 = 13 ....checks

For even squares, it is even easier, because

G2(n) = 2L = 2(n+2)

check:

for n=2, square 2 has 2(2+2) = 8 green squares........checks

for n=4, square 4 has 2(4+2) = 12 green squares........checks.

Fincally, we apply our formula to n=20 and n=21

square 20 : G2(20) = 2(n+2) = 2(20+2) = 44 green quars

square 21 : G1(21) = 2n+3 = 2(21)+3 = 45 green squares

5 0
2 years ago
Please help me simplify these expressions
Rina8888 [55]

Answer:

4. -2s^9

7. 8b^10

Step-by-step explanation:

First, focus on the number part of the expression. For 4), multiply -2 x -1 x -1 = -2. Then, look at the exponents. When you're multiplying exponents with the same base (in number 4, the base is s), you can add the exponents.

2+3+4 = 9; which makes it s^9. Multiply -2 x s^9, which gives you -2s^9.

Same thing for 7). Multiply all the numbers first. this gives you 8. (Remember two negatives equals a positive). Add all of the exponents of b together, which gives you 10. (when a variable has no exponent, it means that the exponent is 1.) Multiplying 8 and b^10 should give you 8b^10.

It may help to brush up on exponent rules and sign rules.

6 0
3 years ago
A: 1/5 units<br> B: 4 units<br> C: 15.5 units<br> D: 24 units<br> E: 18 units<br> With screenshot
Sedaia [141]
E 18 the answer is 18 E
4 0
3 years ago
Read 2 more answers
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