Easy, 15 feet. If he dived 12 the first time and three more than his first the second time you just have to add 3 + 12
To solve for the time it reach the maximum height, you must solve the first derivative of the function and equate it to zero
<span>h(t) = −4.9t^2 + 14.7t + 1</span>
dh/ dt = -9.8t + 14.7
then equate to zero
-9.8t + 14.7 = 0
solve for t
t = 1.5 s
then the maximum height is when t = 1.5
<span>h(t) = −4.9t^2 + 14.7t + 1
h(1.5) = </span><span>−4.9(1.5)^2 + 14.7(1.5) + 1
h(1.5) = 12.025 m
</span>
There are many answers o this question
just think,
for example, a truck driver is asked to load a bunch of tomato crates onto his truck, which can only carry 1 tonne, how is he gonna know the number of tomato crates his truck can carry?
Answer:
C. -186,205
Step-by-step explanation:
636,854 - 827,155 + 684,862 - 680,766
=> 1,321,716 - 1,507,921
=> -186,205
Since both have same speed
v(rel.) x-(-x)= 10( from law of vector addition)
2x=10,x= 5m/sec
