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Nana76 [90]
3 years ago
10

Solving a System: No Solution

Mathematics
1 answer:
umka21 [38]3 years ago
6 0

Answer 15

Step-by-step explanation:

21 minus 5 is 16 munus 1 is 15 duh

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3 1/5 x 2 3/4= <br><br> In lowest terms
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Step-by-step explanation:

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7 0
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Help mi plzz.........​
faust18 [17]
Tan3A=tan(2A+A)

We know that , tan(x+y)=(tanx + tany)/(1 - (tanx)(tany))

tan(2A+A)=(tan2A+tanA)/(1 - (tan2A)(tanA))— (1)

We know that , tan2x=2tanx/(1 - tan^2x)

So, by substituting tan2A in (1),we get,

=[2tanA/(1 - tan^2A) + tanA]/1- (2tanA/(1 - tan^2A))(tanA)]

=[2tanA+tanA - tan^3A]/[1 - tan^2A - 2tan^2A]

=[3tanA - tan^3A]/[1-3tan^2A]

Therefore, tan3A= [3tanA - tan^3A]/[1-3tan^2A]

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3 years ago
What is five million, one hundred fifteen written in standard form?
Kamila [148]
5,000,115

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A

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