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2 years ago

Cashews cost $6.75/lb. and Jeanna can spend at most $30 for them. How many pounds can she buy?

Mathematics

2 answers:

Vika [28.1K]2 years ago

6 0

Answer:

4.44 lb

Step-by-step explanation:

$6.75 ---> 1 lb

$1 ---> (1/6.75) lb

$30 ---> [$30* (1/6.75)] lb

$30 ---> 4.44

So she can buy most 4.44 lb of pounds

Step-by-step explanation:

pls branliest to me he/she have 210 me onley 4

Harman [31]2 years ago

4 0

Answer:

4.44 lb

Step-by-step explanation:

$6.75 ---> 1 lb

$1 ---> (1/6.75) lb

$30 ---> [$30* (1/6.75)] lb

$30 ---> 4.44

So she can buy most 4.44 lb of pounds

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x-intercepts of $\mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})$

SOLUTION:

Given, $f(x)=x^{2}+12 x+24$ -- eqn 1

x-intercepts of the function are the points where function touches the x-axis, which means they are zeroes of the function.

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$X=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Here, for (1) a = 1, b= 12 and c = 24

$X=\frac{-(12) \pm \sqrt{(12)^{2}-4 \times 1 \times 24}}{2 \times 1}$

$\begin{array}{l}{X=\frac{-12 \pm \sqrt{144-96}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{48}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{16 \times 3}}{2}} \\\\ {X=\frac{-12 \pm 4 \sqrt{3}}{2}} \\ {X=\frac{2(-6+2 \sqrt{3})}{2}, \frac{2(-6-2 \sqrt{3})}{2}} \\\\ {X=(-6+2 \sqrt{3}),(-6-2 \sqrt{3})}\end{array}$