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pogonyaev
2 years ago
8

At the accounting break-even point, Swiss Mountain Gear sells 22,940 ski masks at a price of $19 each. At this level of producti

on, the depreciation is $67,000 and the variable cost per unit is $6. What is the amount of the fixed costs at this production level?
Physics
1 answer:
gogolik [260]2 years ago
8 0

Answer:

fixed cost $231220

Explanation:

given data:

quantity of skl mask = 22,940

skl mass rate = $19 each

variable cost = $6 per unit

therefore

Contribution/unit of ski mask  = 19 - 6 = $13

for 22940 ski masks, total cost =  (22940*13) =  298220

Depreciation cost  $67000

fixed cost is = 298220 - 67000 = $231220

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Answer:

prokaryotic cells have no nucleus but contain DNA.

I hope this helps

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3 years ago
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How long does it take for an airplane to change its velocity from 140 m/s to 180 m/s if its
kobusy [5.1K]

Answer:

Explanation:

a = 4ms⁻²,  Vf = 180 m/s  &  Vi = 140m/s

a = \frac{Vf-Vi}{t}

4 = \frac{180-140}{t}

t = 40/4

t = 10sec

To Measure Distance Use third Equation of Motion:

2aS = Vf²-Vi²

S = \frac{180*180 - 140*140}{2(4)}

S = 12800/8 = 1600m

4 0
3 years ago
Robin is standing terrified at the end of a diving board, which is high above the water. If Robin has a mass of 76 kg and is sta
masya89 [10]

Answer:

 Torque = 1191.68 N-m

Explanation:

Given data

mass m = 76 kg

standingdistance r  = 1.6 m

Solution

we get here torque  that si express as

torque  = force × distance ................1

torque  = r × F sin(theta)

and we know that

F = mg   .........2

and g = 9.8 m/s²

put here value in equation 1 we get

Torque = 76 × 1.6 × 9.8 × sin(90)

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2 years ago
Think of pushing a heavy object to make it slide across the floor (like a big, heavy box with
laiz [17]

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heavy box with no heels on it

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2 years ago
A basketball player standing up with the hoop launches the ball straight up with an initial velocity of v_o = 3.75 m/s from 2.5
denis23 [38]

Answer:

a) The maximum height the ball will achieve above the launch point is 0.2 m.

b) The minimum velocity with which the ball must be launched is 4.43 m/s or 0.174 in/ms.

Explanation:

a)

For the height reached, we use 3rd equation of motion:

2gh = Vf² - Vo²

Here,

Vo = 3.75 m/s

Vf =  0m/s, since ball stops at the highest point

g = -9.8 m/s² (negative sign for upward motion)

h = maximum height reached by ball

therefore, eqn becomes:

2(-9.8m/s²)(h) = (0 m/s)² - (3.75 m/s²)²

<u>h = 0.2 m</u>

b)

To find out the initial speed to reach the hoop at height of 3.5 m, we again use 3rd eqn. of motion with h= 3.5 m - 2.5m = 1 m (taking launch point as reference), and Vo as unknown:

2(-9.8m/s²)(1 m) = (0 m/s)² - (Vo)²

(Vo)² = 19.6 m²/s²

Vo = √19.6 m²/s²

<u>Vo = 4.43 m/s</u>

Vo = (4.43 m/s)(1 s/1000 ms)(39.37 in/1 m)

<u>Vo = 0.174 in/ms</u>

<u />

6 0
2 years ago
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