I think F= mv²/r
And F=ma
So, ma = mv²/r
a = v²/r
a = 100/5
a = 20 m/s
The Action Force of this scenario is the pushing force of the Diver. The Reaction Force is the raft pushing back on the diver.
The Third Law of Motion states that "For every action, there is an equal and opposite reaction." Now when the diver dives off the raft, the raft is also pushing the same amount of force as the diver did as he dives off. The diver will then move forward and the raft on the other hand will move backwards.
The movement of the raft shows the opposite force. It will move backwards depending on how strong the diver will push off on the raft. And the amount of force he pushes on it, the raft will exert the same force so the stronger the force of the diver, the farther he will go because the raft will push him in that same direction as it goes backwards.
Impulse = mass * volume is the most common equation, but you can also calculate impulse by Force * time. So if we increase the force we need to decrease the time.
800,000 km/hr is the answr
Answer:
The spring constant is 215.6 N/m.
Explanation:
Given that,
Distance = 39 cm
Compresses length = 29 cm
Mass = 2.2 kg
We need to calculate the distance
Using formula of distance
Put the value into the formula
We need to calculate the spring constant
Using formula of restoring force
Where, F = force
x = distance
Put the value into the formula
Hence, The spring constant is 215.6 N/m.
