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2 years ago

7

Sticky question: how do you separate molecules that are attracted to one another?.

1 answer:

lions [1.4K]2 years ago

3 0

Answer:

Chromatography uses chromatography paper which is filter paper that is made of cellulose, a polymer. Cellulose is polar, therefore it attracts water molecules, as well as other polar substances. As the solvent reacts with the paper, it competes for the attraction of the molecules being separated.

Explanation:

hope it helps

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How many kilojoules are released when 12.0 g of propane, C3H8, reacts?

NeTakaya

Answer:

9/11 happened on the 11th of September

4 0

2 years ago

Which of the following forms a new substance? melting, evaporating, freezing or burning

Slav-nsk [51]

It would be burning be cause when you freeze, evaporate, or melt anything it is just changing how fast the atoms are moving . Think of it like water, ice, and steam, they are all the same thing but in different forms because of melting, evaporating,and melting. Burning is breaking it down.

4 0

4 years ago

Read 2 more answers

The combustion of 1.5011.501 g of fructose, C6H12O6(s)C6H12O6(s) , in a bomb calorimeter with a heat capacity of 5.205.20 kJ/°C

avanturin [10]

Answer : The internal energy change is -2805.8 kJ/mol

Explanation :

First we have to calculate the heat gained by the calorimeter.

$q=c\times (T_{final}-T_{initial})$

where,

q = heat gained = ?

c = specific heat = $5.20kJ/^oC$

$T_{final}$ = final temperature = $27.43^oC$

$T_{initial}$ = initial temperature = $22.93^oC$

Now put all the given values in the above formula, we get:

$q=5.20kJ/^oC\times (27.43-22.93)^oC$

$q=23.4kJ$

Now we have to calculate the enthalpy change during the reaction.

$\Delta H=-\frac{q}{n}$

where,

$\Delta H$ = enthalpy change = ?

q = heat gained = 23.4 kJ

n = number of moles fructose = $\frac{\text{Mass of fructose}}{\text{Molar mass of fructose}}=\frac{1.501g}{180g/mol}=0.00834mole$

$\Delta H=-\frac{23.4kJ}{0.00834mole}=-2805.8kJ/mole$

Therefore, the enthalpy change during the reaction is -2805.8 kJ/mole

Now we have to calculate the internal energy change for the combustion of 1.501 g of fructose.

Formula used :

$\Delta H=\Delta U+\Delta n_gRT$

or,

$\Delta U=\Delta H-\Delta n_gRT$

where,

$\Delta H$ = change in enthalpy = $-2805.8kJ/mol$

$\Delta U$ = change in internal energy = ?

$\Delta n_g$ = change in moles = 0 (from the reaction)

R = gas constant = 8.314 J/mol.K

T = temperature = $27.43^oC=273+27.43=300.43K$

Now put all the given values in the above formula, we get:

$\Delta U=\Delta H-\Delta n_gRT$

$\Delta U=(-2805.8kJ/mol)-[0mol\times 8.314J/mol.K\times 300.43K$

$\Delta U=-2805.8kJ/mol-0$

$\Delta U=-2805.8kJ/mol$

Therefore, the internal energy change is -2805.8 kJ/mol

5 0

3 years ago

All of the following are strong acids except

IgorC [24]

Answer:

acetic acid

Explanation:

6 0

3 years ago

Read 2 more answers

Find the volume of a gold ring that has a mass of 12.00 grams. The density of gold is 19.30 g/mL. The volume is

kozerog [31]

Answer:

<h3>The answer is 0.622 mL</h3>

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

$volume = \frac{mass}{density} \\$

From the question

mass = 12 g

density = 19.30 g/mL

We have

$volume = \frac{12}{19.30} \\ = 0.62176165...$

We have the final answer as

<h3>0.622 mL</h3>

Hope this helps you

3 0

3 years ago