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4vir4ik [10]
3 years ago
6

What is the difference between red phosphorus and white phosphorus?​

Chemistry
2 answers:
RoseWind [281]3 years ago
8 0

Answer:

White phosphorusRed PhosphorusIt is insoluble in water but soluble in carbon disulphide.It is insoluble in both water and carbon disulphide.It undergoes spontaneous combustion in air.It is relatively

Explanation:

I hope it will help you

oksano4ka [1.4K]3 years ago
3 0

Answer:

<u>Red phosphorus and white phosphorus are two the most common and important allotropes of phosphorus. Red phosphorus is thermally more stable than white phosphorus. It is a white waxy solid. ... It turns yellow in colour in exposure to light, hence, it is also called as yellow phosphorus.</u>

Explanation:

<em>Hope</em><em> </em><em>its</em><em> </em><em>helpful</em><em> </em><em>to</em><em> </em><em>u</em><em> </em>☺✌

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Titanium has an HCP crystal structure, a c/a ratio of 1.669, an atomic weight of 47.87 g/mol, and a density of 4.51 g/cm3. Compu
IrinaK [193]

Answer : The atomic radius for Ti is, 1.45\times 10^{-8}cm

Explanation :

Atomic weight = 47.87 g/mole

Avogadro's number (N_{A})=6.022\times 10^{23} mol^{-1}

First we have to calculate the volume of HCP crystal structure.

Formula used :  

\rho=\frac{Z\times M}{N_{A}\times V} .............(1)

where,

\rho = density  = 4.51g/cm^3

Z = number of atom in unit cell (for HCP = 6)

M = atomic mass  = 47.87 g/mole

(N_{A}) = Avogadro's number  

V = volume of HCP crystal structure = ?

Now put all the values in above formula (1), we get

4.51g/cm^3=\frac{6\times (47.87g/mol)}{(6.022\times 10^{23}mol^{-1}) \times V}

V=1.06\times 10^{-22}cm^3

Now we have to calculate the atomic radius for Ti.

Formula used :

V=6R^2c\sqrt{3}

Given:

c/a ratio = 1.669 that means,  c = 1.669 a

Now put (c = 1.669 a) and (a = 2R) in this formula, we get:

V=6R^2\times (1.669a)\sqrt{3}

V=6R^2\times (1.669\times 2R)\sqrt{3}

V=(1.669)\times (12\sqrt{3})R^3

Now put all the given values in this formula, we get:

1.06\times 10^{-22}cm^3=(1.669)\times (12\sqrt{3})R^3

R=1.45\times 10^{-8}cm

Therefore, the atomic radius for Ti is, 1.45\times 10^{-8}cm

3 0
3 years ago
A chemist is studying the properties of a gas under various conditions. He observes that when the gas is at room temperature and
larisa86 [58]

Answer:

Ideal gas explains the property of gas that has no inter-molecular attractions irrespective of temperature and pressure.

<u>Explanation:</u>

  • Ideal gases assumes that the gases would experience no inter-molecular attraction and collision with other gases.
  • These gases are perfectly exhibiting elastic collision in nature.
  • The particle of gases moves slowly at lower temperature and the gases would become close when they exhibit high pressure.
  • The "closeness of the gas-particle" and "low-speed characteristics" are the important observations noted.
  • The inter-molecular forces deviate the property of gases from ideal gas behavior.
3 0
3 years ago
Read 2 more answers
Which is a characteristic of mixtures ?
lisabon 2012 [21]

The characteristics of mixtures are:

a) they are made up of two of more substances

b) the two substances can be separated by physical means

c) there are two kinds of mixtures : homogenous and heterogenous

d) homogenous mixtures do not have any physicaly distinguished boundary  

7 0
3 years ago
Read 2 more answers
The dust particles in water can be helped to settle down faster by
Korolek [52]
The dust particles in the water can be helped to settle down faster by Alum.

So, your answer is option B. Alum.

Hope this helps!
6 0
3 years ago
The concentration of Fe2 in a sample is determined by measuring the absorbance of its complex with ferroxine. The sample, measur
sdas [7]

Answer:

  • Absorbance of sample solution = 1.21
  • Absorbance of reagent blank = 0.205

Explanation:

In order to solve this problem we need to keep in mind the <em>Lambert-Beer law</em>, which states:

  • A = ε*b*C

Where ε is the molar absorption coefficient, b is the length of the cuvette, and C is the concentration.

By looking at the equation above we can see that if ε and C are constant; and b is 5 times higher (5.00 cm vs 1.00 cm) then the absorbance will be 5 times higher as well:

  • Absorbance of sample solution = 0.242 * 5 = 1.21
  • Absorbance of reagent blank = 0.041 * 5 = 0.205
8 0
3 years ago
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