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dmitriy555 [2]
3 years ago
13

Steven is playing an online video game

Mathematics
1 answer:
astraxan [27]3 years ago
7 0
Steven gained 100 points.

To calculate the gain or lose of any 2 numbers, always do

Final - Initial

So,

-50 - -150

Is like saying

I have negative 50, and I take away negative 150.

Taking away negative numbers is just addition.

-50 + 150 = 100


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Activity
Ierofanga [76]

Answer:

p=0.25

Step-by-step explanation:

Given that a club can select one member to attend a conference. All of the club officers want to attend. There are a total of four officers, and their designated positions within the club are President (P), Vice dash President (Upper V )comma Secretary (Upper S )comma nbspand Treasurer (Upper T ).

Sample space would be

a){ {P}, {V}, {S} {T}} is the sample space with notations standing for as given in the question

b) Each sample is equally likely. Hence we have equal chances for selecting any one out of the four.

If probability of selecting a particular sample of size I is p, the by total probability axiom we have

\begin{gathered}4p =1\\p =0.25\end{gathered}

4p=1

7 0
2 years ago
Can you guys help me please :(
ale4655 [162]

Answer:

720 m²

Step-by-step explanation:

Area = base × height

= 12 × 6

= 72 mm²

≈ 720 m² (1 mm = 10 m)

5 0
2 years ago
Given the terms a10 = 3 / 512 and a15 = 3 / 16384 of a geometric sequence, find the exact value of the term a30 of the sequence.
GenaCL600 [577]
The answer is \frac {3}{2^{29}}
5 0
3 years ago
I need help find the coordinates
stellarik [79]

2×2=4

4÷2=2

4+2=6

4+2+6=12

we know that,

put a number you like anything I will write x°

x°+12°=90°

90°-12°=78°,,

again,

78°-12°=66°,,

now,

remove 6° from 60°

60

-----

12

=5,,

5 0
4 years ago
What is the value of C in the matrix equation below?
lara [203]

Given:

The matrix equation is:

\begin{bmatrix}-18&3&5\end{bmatrix}-C=\begin{bmatrix}-22&1&12\end{bmatrix}

To find:

The value of matrix C.

Solution:

Let A=\begin{bmatrix}-18&3&5\end{bmatrix},B=\begin{bmatrix}-22&1&12\end{bmatrix}. Then the given equation can be rewritten as

A-C=B

-C=B-A

C=-(B-A)

C=A-B

On substituting the values of the matrices, we get

C=\begin{bmatrix}-18&3&5\end{bmatrix}-\begin{bmatrix}-22&1&12\end{bmatrix}

C=\begin{bmatrix}-18-(-22)&3-1&5-12\end{bmatrix}

C=\begin{bmatrix}-18+22&2&-7\end{bmatrix}

C=\begin{bmatrix}-4&2&-7\end{bmatrix}

Therefore, the correct option is C.

6 0
3 years ago
Read 2 more answers
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