Coil the length of 15 centimetres with a cross section of 30 centimetres square has a charge of 250. Inside the coil is a nickel
1 answer:
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Answer:
1) A
2) C
3) B
4) A
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8) A
9) C
10) C
Explanation:
1) m = 15kg, a = , F = ma = 15*10 = 150N
2) m = 3kg, v = , r = 4m, F =
= 12N
3) a = , r = 10m, v=?
F = and F = ma
equating the two equations and cancelling a, we have:
= a
making v the subject of formula, we have:
v =
=
= 10
4) r = 10m, v = , a = ?
F =
F = ma
equating the above equations and making a subject of formula, we get:
a =
a = 25/10 = 2.5
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8) F =
assuming m and r is unity, that is the values are 1 respectively, the formula simplifies to:
F =
Now, if v is tripled
F =
F = 9
We can see that the force will be 9X greater than it was.
9) F =
assuming m and r is unity, that is the values are 1 respectively, the formula simplifies to:
F =
Now, if v is doubled
F =
F = 4
We can see that the force will be 4X greater than it was.
10) F =
assuming m and v is unity, that is the values are 1 respectively
F = 1/r
if r is doubled,
F = 1/2 * 1/r
We can see that the force is 1/2 as big as it was
Ranking of de Broglie wavelengths from largest to smallest is electron > proton > helium
- De Broglie proposed that because light has both wave and particle properties, matter exhibits both wave and particle properties. This property has been explained as the dual behavior of matter.
- From his observations, de Broglie derived the relationship between the wavelength and momentum of matter. This relationship is known as de Broglie's relationship
De Broglie's relationship is given by .....(1) , where λ is known as de Broglie wavelength and m is mass , v is velocity , h = Plank’s constant.
From equation (1) wavelength and mass has an inverse relation .
Mass of helium is 4 times the mass of the proton and proton has a greater mass than electron.
According to equation (1) , less the mass higher will be the wavelength
Hence electron having less mass have higher wavelength and then proton and then helium having large mass will have less wavelength .
Thus, order should be electron > proton > helium .
Learn about de brogile wavelength more here :
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