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4 years ago

Does a calculation lose any information when converted from centimeters to meters? Explain

Physics

1 answer:

german4 years ago

7 0

Answer:

Explanation:

There are many units that are used to measure length of an object. For example centimeters, meters, millimeters etc.

There is a relationship between any of two units to measure lengths. If we want to convert some length from cm to m, it can be done as follows :

1 cm = 0.01 m

1 m = 100 cm

When we use this conversion, the calculation remains the same. Only the way to represent it will be different.

Hence, there is no lose of information when converted from centimeters to meters.

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True or false the potential energy of a freely object increases as it begins to fall

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False, as an object falls its potential energy turns into kinetic energy thus decreasing the potential energy.

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3 years ago

Adding heat energy to liquid H2O (water) causes ______________. a Accumulation b Evaporation c Condensation d Precipitation

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3 years ago

Humans have 46 chromosomes. The cells created by meiosis have

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3 years ago

Ship A is located 4.2 km north and 2.7 km east of ship B. Ship A has a velocity of 22 km/h toward the south and ship B has a vel

kotykmax [81]

Answer:

(a) The x-component of velocity is 31.55 km/h

(b) The y-component of velocity is 44.92 km/hr

Solution:

As per the solution:

The relative position of ship A relative to ship B is 4.2 km north and 2.7 km east.

Velocity of ship A, $\vec{u_{A}}$ = 22 km/h towards South = $- 22\hat{j}$

Velocity of ship B, $\vec{u_{B}}$ = 39 km/h Towards North east at an angle of $36^{\circ}$ = $\vec{u_{B}} = 39sin36^{\circ} \hat{j}$

Now, the velocity of ship A relative to ship B:

$\vec{u_{AB}} = \vec{u_{A}} - \vec{u_{B}}$

$\vec{u_{A}} = - 22\hat{j}$

$\vec{u_{B}} = 39cos36^{\circ} \hat{i} - 39sin36^{\circ} \hat{j}$

Now,

$\vec{u_{AB}} = - 22\hat{j} +39cos36^{\circ} \hat{i} - 39sin36^{\circ} \hat{j}$

$\vec{u_{AB}} = 31.55\hat{i} - 44.92\hat{j}$

4 0

3 years ago

A 6.75 nC charge is located 1.99 m from a 4.46 nC point charge.

sladkih [1.3K]

Explanation:

Given that,

Charge 1, $q_1=6.75\ nC=6.75 \times 10^{-9}\ C$

Charge 2, $q_2=4.46\ nC=4.46\times 10^{-9}\ C$

The distance between charges, r = 1.99 m

To find,

The electrostatic force and its nature

Solution,

(a) The electric force between two charges is given by :

$F=\dfrac{kq_1q_2}{r^2}$

$F=\dfrac{9\times 10^9\times 6.75\times 10^{-9}\times 4.46\times 10^{-9}}{(1.99)^2}$

$F=6.84\times 10^{-8}\ N$

(b) As the magnitude of both charges is positive, then the force between charges will be repulsive.

Therefore, this is the required solution.

5 0

4 years ago