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IceJOKER [234]
3 years ago
7

Visible light travels at a speed 3.0 × 108 of m/s. If red light has a wavelength of 6.5 × 10–7 m, what the frequency of this lig

ht? 2.2 × 10–15 HZ 2.0 × 102 HZ 3.0 × 108 HZ 4.6 × 1014 HZ
Physics
1 answer:
zlopas [31]3 years ago
5 0

Answer:

4.6\cdot 10^{14} Hz

Explanation:

The frequency of an electromagnetic wave is given by:

f=\frac{c}{\lambda}

where

c=3.0\cdot 10^8 m/s is the speed of light

\lambda is the wavelength

Red light has a wavelength of

\lambda=6.5\cdot 10^{-7} m

So by using the formula above we can calculate its frequency:

f=\frac{3.0\cdot 10^8 m/s}{6.5\cdot 10^{-7} m}=4.6\cdot 10^{14} Hz

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4 0
3 years ago
A transformer connected to a 120-v(rms) at line is to supply 13,000V(rms) for a neon sign.
lyudmila [28]

Answer:

(a) 108

(b) 110.500 kW

(c) 920.84 A

Solution:

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Voltage at primary, V_{p} = 120\ V          (rms voltage)

Voltage at secondary, V_{s} = 13000\ V  (rms voltage)

Current in the secondary, I_{s} = 8.50\ mA  

Now,

(a) The ratio of secondary to primary turns is given by the relation:

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N_{p} = No. of turns in primary

N_{s} = No. of turns in secondary

\frac{N_{s}}{N_{p}} = \frac{13000}{120} ≈ 108

(b) The power supplied to the line is given by:

Power, P = V_{s}I_{s} = 13000\times 8.50 = 110.500\ kW

(c) The current rating that the fuse should have is given by:

\frac{V_{s}}{V_{p}} = \frac{I_{p}}{I_{s}}

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