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nadezda [96]
4 years ago
6

An asteroid is speeding directly towards a space ship with a velocity of 255 m/s. If the asteroid is detected 8000 meters from t

he space ship, how long does the crew have to take evasive action before the asteroid hits the ship?
A) about 22.6 seconds
B) about 31.4 seconds
C) about 32.0 seconds
D) about 41.5 seconds
Physics
2 answers:
Softa [21]4 years ago
5 0
B) about 31.4 seconds
Sveta_85 [38]4 years ago
3 0
B) 31.4 I got this by doing 8,000 divided by 255.




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Y_Kistochka [10]

Answer:

thermomiter

Explanation:

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Why does venus appear so bright to the naked eye?
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Venus is the second planet from the sun. It is usually the brightest object in our sky, other than our sun and moon. At sunrise and sunset, it looks like a big, bright star. It is bright because Venus has a cloud cover that reflects the sunlight. These clouds are made up of gases.

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4 years ago
Given the thermochemical equations X2+3Y2⟶2XY3ΔH1=−370 kJ X2+2Z2⟶2XZ2ΔH2=−120 kJ 2Y2+Z2⟶2Y2ZΔH3=−270 kJ Calculate the change in
Alchen [17]

Answer : The change in enthalpy of the reaction is, -310 kJ

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

The given main reaction is,

4XY_3+7Z_2\rightarrow 6Y_2Z+4XZ_2    \Delta H=?

The intermediate balanced chemical reaction will be,

(1) X_2+3Y_2\rightarrow 2XY_3     \Delta H_1=-370kJ

(2) X_2+2Z_2\rightarrow 2XZ_2    \Delta H_2=-120kJ

(3) 2Y_2+Z_2\rightarrow 2Y_2Z    \Delta H_3=-270kJ

Now we will reverse the reaction 1 and multiply reaction 1 by 2, reaction 2 by 2 and reaction 3 by 3 then adding all the equations, we get :

(1) 4XY_3\rightarrow 2X_2+6Y_2     \Delta H_1=2\times (+370kJ)=740kJ

(2) 2X_2+4Z_2\rightarrow 4XZ_2    \Delta H_2=2\times (-120kJ)=-240kJ

(3) 6Y_2+3Z_2\rightarrow 6Y_2Z    \Delta H_3=3\times (-270kJ)=-810kJ

The expression for enthalpy of formation of CH_4 will be,

\Delta H=\Delta H_1+\Delta H_2+\Delta H_3

\Delta H=(+740kJ)+(-240kJ)+(-810kJ)

\Delta H=-310kJ

Therefore, the change in enthalpy of the reaction is, -310 kJ

5 0
4 years ago
A 35-gram stainless steel ball on a track is moving at a velocity of 9 m/s. On the same track, a 75-gram stainless steel ball is
elena-s [515]

Answer:

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worty [1.4K]
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