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nadezda [96]
3 years ago
6

An asteroid is speeding directly towards a space ship with a velocity of 255 m/s. If the asteroid is detected 8000 meters from t

he space ship, how long does the crew have to take evasive action before the asteroid hits the ship?
A) about 22.6 seconds
B) about 31.4 seconds
C) about 32.0 seconds
D) about 41.5 seconds
Physics
2 answers:
Softa [21]3 years ago
5 0
B) about 31.4 seconds
Sveta_85 [38]3 years ago
3 0
B) 31.4 I got this by doing 8,000 divided by 255.




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Volumetric cylinders and volumetric flasks

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Two electric charges, held a distance, dd, apart experience an electric force of magnitude, FF, between them. If one of the char
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In this case, we have q_1'=2q_1:

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3 0
3 years ago
An object is thrown upward with some velocity. If the object rises 77.5 m above the point of release, (a) how fast was the objec
jolli1 [7]

Answer:

v_o=39\ m/s\\t_m=4\ s

Explanation:

<u>Vertical Launch Upwards</u>

In a vertical launch upwards, an object is launched vertically up from a height H without taking into consideration any kind of friction with the air.

If vo is the initial speed and g is the acceleration of gravity, the maximum height reached by the object is given by:

\displaystyle h_m=H+\frac{v_o^2}{2g}

The object referred to in the question is thrown from a height H=0 and the maximum height is hm=77.5 m.

(a)

To find the initial speed we solve for vo:

\displaystyle v_o=\sqrt{2gh_m}

v_o=\sqrt{2\cdot 9.8\cdot 77.5}

v_o=39\ m/s

(b)

The maximum time or the time taken by the object to reach its highest  point is calculated as follows:

\displaystyle t_m=\frac{v_o}{g}

\displaystyle t_m=\frac{39}{9.8}

t_m=4\ s

7 0
3 years ago
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