i dont get it so much but
The weight of the bag pack is 8.2 N. g = 1.64 m/s2. Hence, the acceleration due to gravity on moon is 1.64 m/s2. sooo? is it right
Resitance (R)= 10 Ohm
Potential difference (V) = 9V
V= IR
I= V/R
I= 9/10
I= 0.9 Ampere
Therefore 0.9 Ampere of current is flowing through the circuit.
Answer:
By the information given, I am not sure how the event has played out. However, using common knowledge, I can give a scenario of how it may play out.
When removing the first block (the foundation), gravity will pull the other blocks down, as the strength of gravity exceeds that of the strength of air holding it up. This means that all the blocks on top would fall.
By definition of Newton's 1st - 3rd laws, the blocks would not move unless a force is given to it (i.e., removing the bottom block, which causes gravity). Gravity would pull the other blocks downwards. This would lead to the falling of the stack of blocks.
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Answer:
The mailbag will take 2.44 seconds to reach the ground.
Explanation:
The height of a helicopter above the ground is given by:

Height of helicopter at t = 2.10 seconds

The helicopter releases a small mailbag from the height of 29.17 m.
The initial velocity of mailbag = u = 0 m/s
Duration in which mailbag will reach the ground = T
Acceleration due to gravity = g = 
Using second equation of motion ;

We have , s = 29.17
u = 0 m/s
t = T

Solving for T, we gte :
T = 2.44 seconds
The mailbag will take 2.44 seconds to reach the ground.
Answer:
2 m/s²
30 m/s
Explanation:
1) F = ma
1000 N = (500 kg) a
a = 2 m/s²
2) Given:
v₀ = 0 m/s
a = 2 m/s²
t = 15 s
Find: v
v = at + v₀
v = (2 m/s²) (15 s) + 0 m/s
v = 30 m/s