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Arturiano [62]
2 years ago
15

the volume of a water tank is 5m×4m×2m. If the tank is half filled with water. calculate the pressure exerted at the bottom of t

he tank​
Physics
1 answer:
Natali5045456 [20]2 years ago
5 0

Answer:

10⁴ Pa

Explanation:

  • Volume = 5m * 4m * 2m

When the tank is half filled ,

  • Volume = 5m * 4m * 1m = 20m³

Also we know that ,

  • Density of water = 10³ kg/ m³

\longrightarrow Density = Mass/Volume

\longrightarrow 10³ kg/m³ = m/20m³

\longrightarrow m = 2 * 10⁴ kg

So that ,

\longrightarrow Weight = mg

\longrightarrow F = 2*10⁴ × 10 N

\longrightarrow F = 2 * 10⁵ N

And ,

\longrightarrow Pressure = Force/Area

\longrightarrow P = 2 *10⁵/ 5 * 4 Pa

\longrightarrow P = 10⁴ Pa

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Romashka-Z-Leto [24]

Answer:

F = \frac{-Gm_{1}m_{2} }{r^{2} }.

Explanation:

Gravitational force between two objects of masses m_{1},  m_{2} kept at a distance r is given by the formula

F = \frac{-Gm_{1}m_{2} }{r^{2} }

Here ,m_{1} = 2m

         m_{2} = \frac{m}{2}

         

Thus , F = \frac{-G.2m.\frac{m}{2} }{r^{2} }

          F = \frac{-Gm_{1}m_{2} }{r^{2} }.

7 0
3 years ago
While playing baseball with your friends your hands begin to sting after you ctach several fast balls.
muminat

Answer:

Explanation:

To stop a ball with high momentum in a small-time imparts a high amount of impact on hands. This is the reason for the stinging of hands.

The momentum of the ball is due to the mass and velocity. To prevent stinging in the hand one needs to lower his hands to increase the time of contact. In this way, the momentum transfer to the hands will be lesser.        

7 0
3 years ago
The spring constant for the spring in above Table is 20 N/m.
satela [25.4K]
The answer is 0.025J.

W=1/2*k*x^2
W=1/2*20*0.050^2
W=0.025J
5 0
2 years ago
A 2.0 m × 4.0 m flat carpet acquires a uniformly distributed charge of −10 μC after you and your friends walk across it several
mamaluj [8]

Answer:

The  charge on the dust particle is  q_d  = 6.94 *10^{-13} \  C

Explanation:

From the question we are told that

    The length is  l = 2.0 \ m

    The width is  w = 4.0 \ m

   The charge is  q =  -10\mu C= -10*10^{-6} \ C

    The mass suspended in mid-air is m_a =  5.0 \mu g =  5.0 *10^{-6} \ g =  5.0 *10^{-9} \  kg

   

Generally the electric field on the carpet is mathematically represented as

           E =  \frac{q}{ 2 *  A  *  \epsilon _o}

Where \epsilon _o is the permittivity of free space with value \epsilon_o = 8.85*10^{-12}  \ \  m^{-3} \cdot kg^{-1}\cdot  s^4 \cdot A^2

substituting values

           E =  \frac{-10*10^{-6}}{ 2 *  (2 * 4 )  *  8.85*10^{-12}}

           E = -70621.5 \  N/C

Generally the electric force keeping the dust particle on the air  equal to the force of gravity acting on the particles

        F__{E}} =  F__{G}}

=>     q_d *  E  =  m * g

=>      q_d  =  \frac{m * g}{E}

=>      q_d  =  \frac{5.0 *10^{-9} * 9.8}{70621.5}

=>     q_d  = 6.94 *10^{-13} \  C

4 0
3 years ago
Two strong magnets were brought close to each other. They were repelling each other. Explain what must have happened.​
r-ruslan [8.4K]

When two magnets are brought together, the opposite poles will attract one another, but the like poles will repel one another. This is similar to electric charges. Like charges repel, and unlike charges attract.

pls. mark brainliest am. dyning for it

8 0
2 years ago
Read 2 more answers
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