The relation of the temperature and pressure of gas is proportional; if the temperature raises, the pressure will raise at the same rate.
<span>Using conservation of energy and momentum you can solve this question. M_l = mass of linebacker
M_ h = mass of halfback
V_l = velocity of linebacker
V_h = velocity of halfback
So for conservation of momentum,
rho = mv
M_l x V_li + M_h x V_hi = M_l x V_lf + M_h x V_hf
For conservation of energy (kinetic)
E_k = 1/2mv^2/ 1/2mV_li^2 + 1/2mV_{hi}^2 = 1/2mV_{lf}^2 + 1/2mV_{hf}^2
Where i and h stand for initial and final values.
We are already told the masses, \[M_l = 110kg\] \[M_h = 85kg\] and the final velocities \[V_{fi} = 8.5ms^{-1}\] and \[V_{ih} = 7.2ms^{-1} </span>
Answer:
Pressure = 20 MPa
Explanation:
Given:
Force acting on the shoe is,
Area of shoe on which the force acts is,
Now, first we convert the area into its standard unit of m².
We have the conversion factor as:
1 cm² =
Therefore, the area of shoe in square meters is given as:
Now, pressure on the shoe is given as:
Plug in 100 N for 'F', for 'A' and solve for 'P'. This gives,
Now, we know that,
Therefore, the pressure acting on the shoe is 20 MPa.
Answer:
Explanation:
For the first ball, the moment of inertia and the kinetic energy is:
So, replacing, we get that:
At the same way, the moment of inertia and kinetic energy for second ball is:
So:
Then, is equal to , so:
Finally, solving for , we get:
<h3><u>Answer;</u></h3>
B.virtual , upright & larger
<h3><u>Explanation;</u></h3>
- When an object is placed between the focal point and vertex then a virtual image is formed behind the mirror.
- Since the rays reflected from the mirror do not intersect, their extensions behind the mirror intersect and virtual image is formed. The Image is magnified in size and erect unlike the real images.