3 years ago

8.) Plot its cost function

Mathematics

2 answers:

Taya2010 [7]3 years ago

8 0

here is the cost fn added to the plot

ss7ja [257]3 years ago

5 0

The attached shows the two plots. The break-even points are near
x = 21
x = 256

You might be interested in

What's an equation that the passes through (-6,4) and is parallel to y=1/2x+8

deff fn [24]

By definition, if two lines share the same gradient, they are said to be parallel. So, we know for this equation, it must have a gradient of 1/2.

Now, since the point (-6, 4) passes through the line, we know it must satisfy the equation. Since we have a gradient/slope and a point, we can use the point-gradient form:

$y - y_1 = \frac{1}{2}(x - x_1)$ , where $(x_1, y_1)$ represents the points being passed through.

$y - 4 = \frac{1}{2}(x + 6)$
$2y - 8 = x + 6$
$2y = x + 14$
$y = \frac{1}{2}x + 7$

3 0

3 years ago

What do the following two equations represent?

noname [10]

Answer:

It parallel line.

Step-by-step explanation:

7 0

3 years ago

Mary read a book that had 4200 pages last summer. If it took her 35 days to finish the book. How many pages did she read per day

kari74 [83]

120 Pages.....................

8 0

3 years ago

The perimeter of a rectangle is 128 cm, and the ratio of its sides is 5: 3. Find the area of a rectangle

blondinia [14]

Answer:

Area of the rectangle = $15 cm^2$

Step-by-step explanation:

Perimeter of the rectangle= 128 cm

Ratio of length to width is:

$\frac{Length}{Width}= \frac{5}{3} \\\\Length=5 cm\\\\Width=3 cm$

Area of the rectangle= Length*Width

$=5cm*3cm\\\\=15cm^2$

Area of the rectangle = $15 cm^2$

7 0

3 years ago

Read 2 more answers

Amy walks from point B to point C along the segment BC. Fraser walks from point O to point A along the segment OA. Which stateme

torisob [31]

Based on the graph, point O is the center of the circle.
Segment BC is a chord of the circle that passes through point O, it is a diameter.
Segment OA is a radius of the circle.

The correct statement for this problem is:

<span>Amy walks a distance equal to the diameter, and Fraser walks a distance equal to the radius of the lawn.</span>

3 0

3 years ago