Answer:
There will be $5624.32 in the account after 3 years if the interest is compounded annually.
There will be $5630.812 in the account after 3 years if the interest is compounded semi-annually.
There will be $5634.125 in the account after 3 years if the interest is compounded quarterly.
There will be $5636.359 in the account after 3 years if the interest is compounded monthly
Step-by-step explanation:
Tamira invests $5,000 in an account
Rate of interest = 4%
Time = 3 years
Case 1:
Principal = 5000
Rate of interest = 4%
Time = 3 years
No. of compounds per year = 1
Formula :

A=5624.32
There will be $5624.32 in the account after 3 years if the interest is compounded annually.
Case 2:
Principal = 5000
Rate of interest = 4%
Time = 3 years
No. of compounds per year = 2
Formula : 

A=5630.812
There will be $5630.812 in the account after 3 years if the interest is compounded semi-annually.
Case 3:
Principal = 5000
Rate of interest = 4%
Time = 3 years
No. of compounds per year = 4
Formula : 

A=5634.125
There will be $5634.125 in the account after 3 years if the interest is compounded quarterly.
Case 4:
Principal = 5000
Rate of interest = 4%
Time = 3 years
No. of compounds per year = 4
Formula :

A=5636.359
There will be $5636.359 in the account after 3 years if the interest is compounded monthly
Answer:
The bench costs $350
Step-by-step explanation:
et the cost of the bench = x
the cost of the garden table = x + 94
x + (x + 94) = 794
2x + 94 = 794
2x = 700
x = 350
The bench costs $350 and the garden table costs 350 + 94 = $444
Answer:
x = -11
Step-by-step explanation:
Hello There!
create an equation
x + 51 + 60 + 80 = 180
combine like terms
51 + 60 + 80 = 191
x + 191 = 180
subtract 191 from each side
180 - 191 = -11
we're left with
x = -11
Fraction: 1/512
decimal: 0.001953