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2 years ago

Identify the elements with the following electronic configurations; 1s22s22p63s23p64s23d3

Chemistry

1 answer:

Whitepunk [10]2 years ago

5 0

~Shoto Todoroki here~

<h2>If you are referring to a neutral atom, then Vanadium (V) has that particular electron configuration.</h2>

Remember that for neutral atoms, the number of electrons must equal the atomic number. Adding up all the electrons from the given configuration will give

This means that the atom you're looking for has an atomic mass of 23, which corresponds to the atomic mass of Vanadium, a transition metal located in the fourth row, group 5 of the periodic table.

Vanadium's noble gas shorthand notation is

V:[Ar]4s23d3

hope this helps :))

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Starting with the partially balanced equation, C2H5OH(l)+?O2(g)→2CO2(g)+3H2O(l) what coefficient should be placed in front of O2

SpyIntel [72]

Answer: The coefficient '3' should be placed infront of oxygen gas to balance the oxygen atoms.

Explanation:

Law of conservation of mass states that mass can neither be created nor be destroyed but it can only be transformed from one form to another form.

This also means that total mass on the reactant side must be equal to the total mass on the product side.

A balanced chemical equation is defined as the equation in which total number of individual atoms on the reactant side is equal to the total number of individual atoms on product side.

For the given chemical reaction, the balanced equation follows:

$C_2H_5OH(l)+3O_2(g)\rightarrow 2CO_2(g)+3H_2O(l)$

By Stoichiometry of the reaction:

1 mole of ethanol reacts with 3 moles of oxygen gas to produce 2 moles of carbon dioxide gas and 3 moles of water molecule

Hence, the coefficient '3' should be placed infront of oxygen gas to balance the oxygen atoms.

5 0

3 years ago

What ions are present when (nh4)2so4 is dissolved in water?

maksim [4K]

NH $NH_{4} ^{+}, SO _{4} ^{2-}$ are the two ions

8 0

3 years ago

Consider the malate dehydrogenase reaction from the citric acid cycle. Given the listed concentrations, calculate the free energ

Ahat [919]

Answer: The Gibbs free energy of the reaction is 21.32 kJ/mol

Explanation:

The chemical equation follows:

$\text{Malate }+NAD^+\rightleftharpoons \text{Oxaloacetate }+NADH$

The equation used to Gibbs free energy of the reaction follows:

$\Delta G=\Delta G^o+RT\ln K_{eq}$

where,

$\Delta G$ = free energy of the reaction

$\Delta G^o$ = standard Gibbs free energy = 29.7 kJ/mol = 29700 J/mol (Conversion factor: 1 kJ = 1000 J)

R = Gas constant = 8.314J/K mol

T = Temperature = $37^oC=[273+37]K=310K$

$K_{eq}$ = Ratio of concentration of products and reactants = $\frac{\text{[Oxaloacetate]}[NADH]}{\text{[Malate]}[NAD^+]}$

$\text{[Oxaloacetate]}=0.130mM$

$[NADH]=2.0\times 10^2mM$

$\text{[Malate]}=1.37mM$

$[NAD^+]=490mM$

Putting values in above expression, we get:

$\Delta G=29700J/mol+(8.314J/K.mol\times 310K\times \ln (\frac{0.130\times 2.0\times 10^2}{1.37\times 490}))\\\\\Delta G=21320.7J/mol=21.32kJ/mol$

Hence, the Gibbs free energy of the reaction is 21.32 kJ/mol

4 0

3 years ago

What are the variables in Gay-Lussac’s law?

labwork [276]

This law states that the pressure of a given amount of gas held at constant volume is directly proportional to the Kelvin temperature. Therefore, the variables are pressure and temperature. Hope this answers the question. Have a nice day.

6 0

3 years ago

Calculate the vapor pressure of water above a solution prepared by dissolving 28.5 g of glycerin (c3h8o3) in 135 g of water at 3

pshichka [43]

Data:

Solute: 28.5 g of glycerin (C3H8O3)
Solvent: 135 g of water at 343 k.
Vapor pressure of water at 343 k: 233.7 torr.

Quesiton: Vapor pressure of water

Solution:

Raoult's Law: The vapour pressure of a solution of a non-volatile solute is equal to the vapour pressure of the pure solvent at that temperature multiplied by its mole fraction.

Formula: p = Xsolvent * P pure solvent

X solvent = moles solvent / moles of solution

molar mass of H2O = 2*1.0g/mol + 16.0 g/mol = 18.0 g/mol

moles of solvent = 135 g of water / 18.0 g/mol = 7.50 mol

molar mass of C3H8O3 = 3*12.0 g/mol + 8*1 g/mol + 3*16g/mol = 92 g/mol

moles of solute = 28.5 g / 92.0 g/mol = 0.310 mol

moles of solution = moles of solute + moles of solvent = 7.50mol + 0.310mol = 7.810 mol

Xsolvent = 7.50mol / 7.81mol = 0.960

p = 233.7 torr * 0.960 = 224.4 torr

Answer: 224.4 torr

8 0

3 years ago