Answer:
The correct answer is: K'= 0.033.
Explanation:
The formation of HI from H₂ and I₂ is given by:
H₂ + I₂ → 2 HI K= 29.9
The decomposition of HI is the reverse reaction of the formation of HI:
2 HI → H₂ + I₂ K'
Thus, K' is the equilibrium constant for the reverse reaction of formation of HI. It is calculated as the reciprocal of the equilibrium constant of the forward reaction (K):
K' = 1/K = 1/(29.9)= 0.033
Therefore, the equilibrium constant for the decomposition of HI is K'= 0.033
I say C because why would you want a plant to resist something that helps it grow? A, B, and D make sense because those can improve the quality of the plant, but fertilizer can improve plant quality and help it grow. So there is no reason to resist it.
Answer:
YES
Explanation:
WE use science cause it is all aaprindhs and science us everywhere .
The pH at the equivalence point always not equal to 7 in a neutralization titration when titration occur between weak acid and weak base , strong acid and weak base or strong base weak acid. The reason behind it is given as,
- At equivalence point the product is present by reacting from acid and base.
- So, when weak acid titrate with strong base then the solution will be weak base at equivalence point.
When strong acid is neutralize with strong base then it form neutral product at the equivalence point. Hence the final conclusion is that the pH of the solution in which titration is takes place between strong acid and strong base is 7 that is neutral left titration between all type of acids and bases ha pH not equal to 7 .
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Answer: Option (c) is the correct answer.
Explanation:
Wood is a mixture of different substances. Primarily it consists of cellulose, lignin, water etc.
When we heat wood then all these substance oxidize into the atmosphere even before they could melt.
Whereas iron, sodium chloride and ethanol all are the substances which can melt at any temperature.
Thus, we can conclude that out of the given options, wood, a mixture of different substances is a material that does not melt at any temperature.
