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3 years ago

What ions are present when (nh4)2so4 is dissolved in water?

Chemistry

1 answer:

maksim [4K]3 years ago

8 0

NH $NH_{4} ^{+}, SO _{4} ^{2-}$ are the two ions

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What type of cryptography uses two keys instead of just one, generating both a private and a public key?

Alexxx [7]

Answer:

It is known as asymmetric key cryptography it is also called public key cryptography.

Explanation:

Asymmetric key cryptography method makes use of two keys.One is used for encryption and the second one for decryption. The public key serves to encrypt plain text or verify a digital signature, while the private key is used to decrypt or decipher the encrypted text or to create a digital signature.

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3 years ago

Which of the following has no electrons? Use a periodic table. Question 1 options: He 2+ He H– H

UkoKoshka [18]

do you have anymore numbers to add to this problem??

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3 years ago

The lowest parts of a transverse wave are called

Law Incorporation [45]

Its number 3 the troughs

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3 years ago

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Which statement is true of the motion of the ball?

Pepsi [2]

Your answer would be answer choice D. The ball is accelerating as the velocity is increasing at a constant rate.

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♥<em /><em>A.W.E.<u>S.W.A.N.</u></em>♥

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3 years ago

How many moles are represented by 3.01 x10^24 oxygen atoms?

asambeis [7]

<h3>Answer:</h3>

5.00 mol O₂

<h3>General Formulas and Concepts:</h3>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.<u> </u>

<u>Stoichiometry</u>

Using Dimensional Analysis

<h3>Explanation:</h3>

<u>Step 1: Define</u>

3.01 × 10²⁴ atoms O₂

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

Set up: $\displaystyle 3.01 \cdot 10^{24} \ atoms \ O_2(\frac{1 \ mol \ O_2}{6.022 \cdot 10^{23} \ atoms \ O_2})$
Multiply/Divide: $\displaystyle 4.99834 \ mol \ O_2$

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

4.99834 mol O₂ ≈ 5.00 mol O₂

4 0

3 years ago