Answer:
Explanation:
A 12.48 g sample of an unknown metal, heated to 99.0 °C was then plunged into 50.0 mL of 25.0 °C water. The temperature of the water rose to 28.1 Go to calculating final temperature when mixing two samples of water ... Problem #1: A 610. g piece of copper tubing is heated to 95.3 °C and placed in an ... The two rings are heated to 65.4 °C and dropped into 12.4 mL of water at 22.3 °C. ... Problem #4: A 5.00 g sample of aluminum (specific heat capacity = 0.89 J g¯1
Answer:
The answer to your question is: density = 4 g/cm³
Explanation:
Data
Volume = 100 cm³
Mass = 400 g
Density = ?
Formula
density = mass/volume
substitution
density = 400/100 = 4 g/cm³
Answer:
(edit: nvm I figured it out, here is the answer)
Explanation:
