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3 years ago

What is the second step in the classification of living things?

Chemistry

2 answers:

frozen [14]3 years ago

8 0

Answer:

B.) Assigning them to any of the 3 domains

Explanation:

The second step in the classification of living beings is to assign them to any of the three domains. There are not six domains. Furthermore, there are neither six nor three kingdoms, there are 5 kingdoms.

The three domains are:

→ Bacteria Domain: It groups most of the unicellular prokaryotes, such as bacteria and cyanobacteria.

→ Domain Archaea: It groups prokaryotes with different biochemical characteristics and that usually inhabit regions with extreme conditions.

→ Eukaria domain: It groups all unicellular and multicellular eukaryotic organisms, such as fungi, animals, plants and organisms previously classified as protists.

Leya [2.2K]3 years ago

6 0

I'll go with B, have a good day

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3 years ago

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Answer:

Some energy is lost as heat

Explanation:

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3 years ago

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Answer:

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Answer:

Redox

Explanation:

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3 years ago

The iodine "clock reaction" involves the following sequence of reactions occurring in a reaction mixture in a single beaker. 1.

Mars2501 [29]

C: 0.012 mol.

<h3>Explanation</h3>

Start with 0.0020 moles of iodate ions ${\text{IO}_{3}}^{-}$ .

How many moles of iodine $\text{I}_2$ will be produced?

${\text{IO}_{3}}^{-}$ converts to $\text{I}_2$ in the first reaction. The coefficient in front of $\text{I}_2$ is three times the coefficient in front of ${\text{IO}_{3}}^{-}$ . In other words, each mole of ${\text{IO}_{3}}^{-}$ will produce three moles of $\text{I}_2$ . 0.0020 moles of ${\text{IO}_{3}}^{-}$ will convert to 0.0060 moles of $\text{I}_2$ .

How many moles of thiosulfate ions ${\text{S}_2\text{O}_3}^{2-}$ are required?

$\text{I}_2$ reacts with ${\text{S}_2\text{O}_3}^{2-}$ in the second reaction. The coefficient in front of $\text{I}_2$ is twice the coefficient in front of ${\text{S}_2\text{O}_3}^{2-}$ . How many moles of ${\text{S}_2\text{O}_3}^{2-}$ does each mole of $\text{I}_2$ consume? Two. 0.0060 moles of $\text{I}_2$ will be produced. As a result, $2 \times 0.0060 = 0.0120$ moles of ${\text{S}_2\text{O}_3}^{2-}$ will be needed.

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3 years ago