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3 years ago

What is the second step in the classification of living things?

Chemistry

2 answers:

frozen [14]3 years ago

8 0

Answer:

B.) Assigning them to any of the 3 domains

Explanation:

The second step in the classification of living beings is to assign them to any of the three domains. There are not six domains. Furthermore, there are neither six nor three kingdoms, there are 5 kingdoms.

The three domains are:

→ Bacteria Domain: It groups most of the unicellular prokaryotes, such as bacteria and cyanobacteria.

→ Domain Archaea: It groups prokaryotes with different biochemical characteristics and that usually inhabit regions with extreme conditions.

→ Eukaria domain: It groups all unicellular and multicellular eukaryotic organisms, such as fungi, animals, plants and organisms previously classified as protists.

Leya [2.2K]3 years ago

6 0

I'll go with B, have a good day

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Metamorphic rocks with a non-foliated texture show metamorphic change that involves ____.

matrenka [14]

Answer:

b. growth in the size of the mineral grains

Explanation:

Non-foliated texture shown by a metamorphic change is depicted by growth in the size of the mineral grains.

Examples of non-foliated metamorphic rocks are quartzite and marble.
In these metamorphic rocks, mineral grains are not aligned with their long axis.
Non-foliated texture occurs under high temperature and low pressure conditions.
As minerals are able to grow, the size can be used to show a metamorphic change.

8 0

3 years ago

Would you sit with this person at the lunch table?

Kipish [7]

Answer:

Sure because I need more friends

7 0

3 years ago

Read 2 more answers

Federico has two samples of pure water—sample X and sample Y. Sample X has a volume of 1 L, and sample Y has a volume of 10 L. H

Lostsunrise [7]

Answer:

The boiling point of sample X and sample Y are exactly the same.

Explanation:

The difference between sample X and sample Y is that they occupy different volumes. However, they both contain pure water. Remember that pure water has uniform composition irrespective of its volume.

Volume does not affect the boiling point as long as the volume is small enough not to give rise to significant pressure changes in the liquid.

The boiling point of a liquid is the temperature at which the pressure exerted by the surroundings upon a liquid is equaled by the pressure exerted by the vapour of the liquid; under this condition, addition of heat results in the transformation of the liquid into its vapour without raising the temperature.

It can be clearly seen from the above that the volume of a solution of pure water does not affect its boiling point hence sample X and sample Y will have the same boiling point.

8 0

3 years ago

What is the percent of nitrogen in dinitrogen pentoxide?

Lostsunrise [7]

Answer: D.) 25.9%

Explanation:

Dinitrogen pentoxide chemical formular : N2O5

Calculating the molar mass of N2O5

Atomic mass of nitrogen(N) = 14

Atomic mass of oxygen(O) = 16

Therefore molar mass :

N2O5 = (2 × 14) + (5 × 16) = 28 + 80 = 108g/mol

Percentage amount of elements in N205:

NITROGEN (N) :

(Mass of nitrogen / molar mass of N2O5) × 100%

MASS OF NITROGEN = (N2) = 2 × 14 = 28

PERCENT OF NITROGEN : (28/108) × 100%

0.259259 × 100%

= 25.925%

= 25.9%

4 0

3 years ago

A sample of gas has an initial pressure of 1.5 atm, an initial volume of 3.0 L, and an initial temperature of 293K. If the final

Nataliya [291]

Answer:

1.9 L

Explanation:

Step 1: Given data

Initial pressure (P₁): 1.5 atm

Initial volume (V₁): 3.0 L

Initial temperature (T₁): 293 K

Final pressure (P₂): 2.5 atm

Final volume (V₂): ?

Final temperature (T₂): 303 K

Step 2: Calculate the final volume of the gas

If we assume ideal behavior, we can calculate the final volume of the gas using the combined gas law.

P₁ × V₁ / T₁ = P₂ × V₂ / T₂

V₂ = P₁ × V₁ × T₂ / T₁ × P₂

V₂ = 1.5 atm × 3.0 L × 303 K / 293 K × 2.5 atm = 1.9 L

6 0

3 years ago