Question

If C=r+7 and D=-2r+3, find an expression that equals 2C−D in standard form.

Answer 1

4r+11 is the answer

Answer 2

Answer:

$\huge\boxed{\boxed{\bf\:4r + 11}}$

Step-by-step explanation:

Given,

• C = r + 7

• D = - 2r + 3

We need to find the value of 2C - D. To solve this, we need to substitute the values of C & D in the expression.  So,

$\tt\:2\:C - D\\\\\sf\:{Substitute \: the \: given \: values}\\\\\tt\:= 2(r + 7) - (-2r + 3)\\\\\sf\:Now, \: follow \: the \: distributive \:property\\\\\tt\:= 2r + 14 + 2r - 3\\\\\sf\:Rearrange\:the\:terms\\\\\tt\:= 2r + 2r + 14 - 3\\\\\sf\:Do \: the \: required \:arithmetic \: operations\\\\=\boxed{ \bf\:4r + 11}$

$\rule{200}{2}$

• The answer will be 4r + 11 in the standard form.

$\rule{200}{2}$

Hope this helps!