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2 years ago

Indicate the charge the following elements as they achieve the noble gas configuration.

Chemistry

1 answer:

AveGali [126]2 years ago

3 0

Answer:

See explanation

Explanation:

Ga is in group 13 hence it must loose three electrons to form Ga^3+ in order to achieve the noble gas configuration because it has three electrons on its outermost shell.

O is in group 16 hence it must accept two electrons in order to attain the noble gas configuration to form O^2- since oxygen has six electrons on its outermost shell.

Br in group 17 has seven electrons in its outermost shell hence it must form Br^- (gain one electron) in order to attain the noble gas configuration.

P in group 15 must accept three electrons and form P^3- in order to attain the noble gas configuration since it has five electrons on its outermost shell.

S is in group 16 hence it must accept two electrons in order to attain the noble gas configuration to form S^2- since sulphur has six electrons on its outermost shell.

Mg in group 2 has two electrons on its outermost shell and must loose both to attain the noble gas configuration forming Mg^2+.

Al is in group 13 hence it must loose three electrons to form Al^3+ in order to achieve the noble gas configuration because it has three electrons on its outermost shell.

Se is in group 16 hence it must accept two electrons in order to attain the noble gas configuration to form Se^2- since selenium has six electrons on its outermost shell.

Lithium is in group 1 and must loose its only outermost electron in order to attain the noble gas configuration to form Li^+.

Rb is in group 1 and must loose its only outermost electron in order to attain the noble gas configuration to form Rb^+.

As in group 15 must accept three electrons and form As^3- in order to attain the noble gas configuration since it has five electrons on its outermost shell.

I in group 17 has seven electrons in its outermost shell hence it must form I^- (gain one electron) in order to attain the noble gas configuration.

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Según la pregunta;

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Answer:

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Read the explanation below to have a better idea based on the kinetic molecular theory.

Explanation:

Hello in this question we have a container and in it is a single gas molecule. So there is our gas molecule and in fact right there that violates the kinetic molecular theory. Because the kinetic molecular theory thinks of these particles as being dimension less points. Because there is so much space between particles. The particles themselves have such an insignificant volume as they can be thought of as dimension lys points. Okay. But anyway this particle is in rapid motion and this motion is essentially random. So it's moving and it will eventually hit the wall of its container. It's moving rapidly so it's going to hit it pretty quickly and when it hits the wall of that container Yeah, it is going to bounce off when it does that. It's a totally elastic collision. So that means there will be no energy transfer, no energy loss, no energy gained. It will just serve to change the direction of the particle. So when it hits the wall it's going to bounce back off the wall and continue in a straight line until it hits another wall and then it will bounce off that wall and it will continue moving in this motion in this motion its speed is related to the amount of energy it has and therefore its temperature. So if we add heat, it will move faster. If we remove heat or cool it down, it will move slower. So when we remove heat, it will move slower. The kinetic molecular theory says it will be constantly moving As long as it is above absolute zero. It's only at absolute zero or 0 Kelvin, where would stop moving. Okay, so all these things describe its motion. It's in rapid random motion in a straight line until it hits the wall of its container. Then it will rebound without a transfer of any energy. It will be totally elastic collision. If we were to heat it up, it would move faster. If we were to cool it down, it would move more slowly, we would have to cool it all the way down to absolute zero before it would stop moving. Right, so all of these things describe its motion. In terms of that kinetic molecular theory,

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