Answer:
10 km/h
Explanation:
Before calculating the average speed, we need to convert the time taken for the trip from minutes to hours. Since 1 hour cointains 60 minutes, we have:
![1 h: 60 min = t : 30 min\\t=\frac{1 h \cdot 30 min}{60 min}=0.5 h](https://tex.z-dn.net/?f=1%20h%3A%2060%20min%20%3D%20t%20%3A%2030%20min%5C%5Ct%3D%5Cfrac%7B1%20h%20%5Ccdot%2030%20min%7D%7B60%20min%7D%3D0.5%20h)
Karen's average speed is given by:
![v=\frac{d}{t}](https://tex.z-dn.net/?f=v%3D%5Cfrac%7Bd%7D%7Bt%7D)
where
d = 5 km is the distance covered
t = 0.5 h is the time taken for the trip
Substituting into the equation, we find
![v=\frac{5 km}{0.5 h}=10 km/h](https://tex.z-dn.net/?f=v%3D%5Cfrac%7B5%20km%7D%7B0.5%20h%7D%3D10%20km%2Fh)
Answer:
yes
it does you weigh less on the equator than at the North or South Pole, but the difference is small. Note that your body itself does not change. Rather it is the force of gravity and other forces that change as you approach the poles. These forces change right back when you return to your original latitude.
The formula without numbers is
![xf = xi + vxi(t) + \frac{1}{2} (a) {t}^{2}](https://tex.z-dn.net/?f=xf%20%3D%20xi%20%2B%20vxi%28t%29%20%2B%20%20%5Cfrac%7B1%7D%7B2%7D%20%28a%29%20%7Bt%7D%5E%7B2%7D%20)
do the initial velocity would be
8.1 m/s
and the acceleration would be
2.9 m/s^2
Magnitude 17 root
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