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kogti [31]
4 years ago
15

What is the oxidation number of neon

Chemistry
1 answer:
vredina [299]4 years ago
7 0

Answer:

Electron Configuration and Oxidation States of Neon. Electron configuration of Neon is [He] 2s2 2p6. Possible oxidation states are 0. so the answer is 0.

Explanation:

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What is the ionic equation of Aqueous calcium bromide was mixed with aqueous gold(I) perchlorate, and a crystallized gold(I) bro
Bumek [7]

Answer:- 2AuClO_4(aq) + CaBr_2(aq)\rightarrow 2AuBr(s)+ Ca(ClO_4)_2(aq)

Explanations:- It's a double replacement reaction where a precipitate of silver(I)bromide is formed. A dpuble replacement reaction in general looks as AB + CD \rightarrow AD + CB

To balance the equation we need to multiply gold compounds on both sides by 2 and the balanced equation is..

2AuClO_4(aq) + CaBr_2(aq)\rightarrow 2AuBr(s)+ Ca(ClO_4)_2(aq)

6 0
4 years ago
What are the products formed when ethane burns in excess oxygen?
Neporo4naja [7]
2 C2H6 + 7 O2 -> 4CO2 + 6 H2O 
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3 0
3 years ago
A 0.2 g sample of pyrolusite is analyzed for manganese content as follows. Add 50.0 mL of 0.1 M solution of ferrous ammonium sul
enyata [817]

Answer:

66.7%

Explanation:

The reaction for the titration of the excess ferrous ion is:

  • 5Fe⁺² + MnO₄⁻ + 8H⁺ → 5Fe³⁺ + Mn²⁺ + 4H₂O

We calculate the moles of Fe⁺² from the used moles of KMnO₄:

  • 0.02 M * 15.0 mL = 0.30 mmol KMnO₄
  • 0.3 mmol KMnO₄ * \frac{5mmolFe^{+2}}{1mmolKMnO_4} = 1.5 mmol Fe⁺²

Then we substract those 0.30 mmol from the original amount used:

  • 0.1 M * 50.0 mL = 5.0 mmol Fe⁺²
  • 5.0 - 1.5 = 3.5 mmol Fe⁺²

The reaction between ferrous ammonium sulfate and MnO₂ is:

  • 2Fe⁺² + MnO₂ + 4H⁺ → 2Fe³⁺ + Mn²⁺ + 2H₂O

So we convert those 3.5 mmol Fe⁺² that were used in this reaction to MnO₂ moles:

  • 3.5 mmol Fe⁺²  * \frac{1mmolMnO_2}{2mmolFe^{+2}}= 1.75 mmol MnO₂

Then we convert MnO₂ to Mn₃O₄, using the reaction:

  • 3MnO₂ → Mn₃O₄ + O₂
  • 1.75 mmol MnO₂ * \frac{1mmolMn_3O_4}{3mmolMnO_2} = 0.583 mmol Mn₃O₄

Finally we convert Mn₃O₄ moles to grams:

  • 0.583 mmol Mn₃O₄ * 228.82 mg/mmol = 133.40 mg Mn₃O₄

And calculate the percent

  • 0.2 g = 200 mg
  • 133.40 / 200 * 100% = 66.7%
5 0
3 years ago
What kinds of intermolecular attractive forces (dipole-dipole, London, hydrogen bonding) are present in the following substances
garik1379 [7]
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</span><span>For the determination of geometry for the specific examples , use the VSEPR (Valence Shell Electron Pair Repulsion) model and by that determine the geometry.</span>

8 0
3 years ago
Last time I'm asking this, answer, this time, 50 points.
EleoNora [17]

Explanation:

Well i mean clothes so cells make tissues which help organs clothes can technically help you if you fall it has layers so it woulf be as a cell?

6 0
3 years ago
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