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shutvik [7]
3 years ago
9

Please help thank you

Chemistry
2 answers:
azamat3 years ago
8 0
The answer is C. It all depends on the size, shape, and sharpness of the shears, plus the smaller it is the more quickly you can use it, it requires less force, hope this helps!
kondaur [170]3 years ago
6 0

Answer:

C. The hand shears because their shorter handles transfer force more quickly to the cutting blade.

Explanation:

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Is the water density higher than the aluminum density
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Water’s density is 1 g/cm3 and AL is 2700kg/m3
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Which of there is an indication that a chemical reaction has occurred?
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Which is a property of an ideal gas?
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HEY THERE!

THE ANSWER IS: the properties of an ideal gas are: An ideal gas consists of a large number of identical molecules. The volume occupied by the molecules themselves is negligible compared to the volume occupied by the gas. The molecules obey Newton's laws of motion, and they move in random motion.

CREDITS:
<span>physics.bu.edu/~duffy/py105/Idealgas.htm</span>
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How much energy is released when 18.0 g of water at 0°C changes from liquid to solid?
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A 0.223 mole sample of gas is held at 33.0 C and 2.00 atm, What's the volume of the gas? R = 0.0821 L atm / mol K answer soon il
Ghella [55]

Answer:

The volume of the gas is 2.80 L.

Explanation:

An ideal gas is a theoretical gas that is considered to be made up of point particles that move randomly and do not interact with each other. Gases in general are ideal when they are at high temperatures and low pressures.

The Pressure (P) of a gas on the walls of the container that contains it, the Volume (V) it occupies, the Temperature (T) at which it is located and the amount of substance it contains (number of moles, n) are related from the equation known as Equation of State of Ideal Gases:

P*V = n*R*T

where R is the constant of ideal gases.

In this case:

  • P= 2 atm
  • V= ?
  • n=0.223 moles
  • R= 0.0821 \frac{L*atm}{mol*K}
  • T=33 °C= 306 °K (being O°C= 273°K)

Replacing:

2 atm* V= 0.223 moles*0.0821 \frac{L*atm}{mol*K}* 306 K

Solving:

V=\frac{0.223 moles*0.0821\frac{L*atm}{mol*K} * 306 K}{2 atm} \\

V= 2.80 L

<u><em>The volume of the gas is 2.80 L.</em></u>

7 0
3 years ago
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